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(Node.js) Iterate over Direct Child Nodes by IndexDemonstrates some ways to iterate over direct child nodes by index. The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this: <root> <fruit color="red">apple</fruit> <fruit color="green">pear</fruit> <veg color="orange">carrot</veg> <meat animal="cow">beef</meat> <xyz> <fruit color="blue">blueberry</fruit> <veg color="green">broccoli</veg> </xyz> <fruit color="purple">grape</fruit> <cheese color="yellow">cheddar</cheese> </root>
var os = require('os'); if (os.platform() == 'win32') { var chilkat = require('@chilkat/ck-node23-win64'); } else if (os.platform() == 'linux') { if (os.arch() == 'arm') { var chilkat = require('@chilkat/ck-node23-linux-arm'); } else if (os.arch() == 'arm64') { var chilkat = require('@chilkat/ck-node23-linux-arm64'); } else { var chilkat = require('@chilkat/ck-node23-linux-x64'); } } else if (os.platform() == 'darwin') { var chilkat = require('@chilkat/ck-node23-darwin-universal'); } function chilkatExample() { var xml = new chilkat.Xml(); // child: Xml var child; var success; // The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml success = xml.LoadXmlFile("get_child.xml"); if (success !== true) { console.log(xml.LastErrorText); return; } // The NumChildren property contains the number of direct // child nodes. Note: The child nodes under "xyz" are NOT // direct children of "root". Therefore, the "root" node has // 7 direct children console.log("NumChildren = " + xml.NumChildren); // Iterate over the direct children by index. The first child // is at index 0. var i; for (i = 0; i <= xml.NumChildren - 1; i++) { // access the tag and content directly by index: console.log(i + ": " + xml.GetChildTagByIndex(i) + " : " + xml.GetChildContentByIndex(i)); } console.log("-----"); // Do the same as the above loop, but get the child node // and access the Tag and Content properties: for (i = 0; i <= xml.NumChildren - 1; i++) { child = xml.GetChild(i); console.log(i + ": " + child.Tag + " : " + child.Content); } console.log("-----"); // Do the same as the above loop, but instead of creating // a new object instance for each child, call GetChild2 to // update the object's reference instead. for (i = 0; i <= xml.NumChildren - 1; i++) { // Navigate to the Nth child. success = xml.GetChild2(i); console.log(i + ": " + xml.Tag + " : " + xml.Content); // Navigate back up to the parent: success = xml.GetParent2(); } console.log("-----"); // Notice that the Content of the "xyz" node is empty. This is correct. // The "xyz" node has no Content, but 2 direct children } chilkatExample(); |
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