Chilkat HOME .NET Core C# Android™ AutoIt C C# C++ Chilkat2-Python CkPython Classic ASP DataFlex Delphi ActiveX Delphi DLL Go Java Lianja Mono C# Node.js Objective-C PHP ActiveX PHP Extension Perl PowerBuilder PowerShell PureBasic Ruby SQL Server Swift 2 Swift 3,4,5... Tcl Unicode C Unicode C++ VB.NET VBScript Visual Basic 6.0 Visual FoxPro Xojo Plugin
(Xojo Plugin) Iterate over Direct Child Nodes by IndexDemonstrates some ways to iterate over direct child nodes by index. The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this: <root> <fruit color="red">apple</fruit> <fruit color="green">pear</fruit> <veg color="orange">carrot</veg> <meat animal="cow">beef</meat> <xyz> <fruit color="blue">blueberry</fruit> <veg color="green">broccoli</veg> </xyz> <fruit color="purple">grape</fruit> <cheese color="yellow">cheddar</cheese> </root>
Dim xml As New Chilkat.Xml Dim child As Chilkat.Xml Dim success As Boolean // The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml success = xml.LoadXmlFile("get_child.xml") If (success <> True) Then System.DebugLog(xml.LastErrorText) Return End If // The NumChildren property contains the number of direct // child nodes. Note: The child nodes under "xyz" are NOT // direct children of "root". Therefore, the "root" node has // 7 direct children System.DebugLog("NumChildren = " + Str(xml.NumChildren)) // Iterate over the direct children by index. The first child // is at index 0. Dim i As Int32 For i = 0 To xml.NumChildren - 1 // access the tag and content directly by index: System.DebugLog(Str(i) + ": " + xml.GetChildTagByIndex(i) + " : " + xml.GetChildContentByIndex(i)) Next System.DebugLog("-----") // Do the same as the above loop, but get the child node // and access the Tag and Content properties: For i = 0 To xml.NumChildren - 1 child = xml.GetChild(i) System.DebugLog(Str(i) + ": " + child.Tag + " : " + child.Content) Next System.DebugLog("-----") // Do the same as the above loop, but instead of creating // a new object instance for each child, call GetChild2 to // update the object's reference instead. For i = 0 To xml.NumChildren - 1 // Navigate to the Nth child. success = xml.GetChild2(i) System.DebugLog(Str(i) + ": " + xml.Tag + " : " + xml.Content) // Navigate back up to the parent: success = xml.GetParent2() Next System.DebugLog("-----") // Notice that the Content of the "xyz" node is empty. This is correct. // The "xyz" node has no Content, but 2 direct children |
© 2000-2024 Chilkat Software, Inc. All Rights Reserved.