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(Xojo Plugin) GetChild* methodsDemonstrates several of the GetChild* methods. The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this: <root> <fruit color="red">apple</fruit> <fruit color="green">pear</fruit> <veg color="orange">carrot</veg> <meat animal="cow">beef</meat> <xyz> <fruit color="blue">blueberry</fruit> <veg color="green">broccoli</veg> </xyz> <fruit color="purple">grape</fruit> <cheese color="yellow">cheddar</cheese> </root> The output XML is this: <abc b="pear" c="orange" a="130">Test</abc>
Dim xml As New Chilkat.Xml Dim child As Chilkat.Xml Dim success As Boolean // The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml success = xml.LoadXmlFile("get_child.xml") If (success <> True) Then System.DebugLog(xml.LastErrorText) Return End If // The NumChildren property contains the number of direct // child nodes. Note: The child nodes under "xyz" are NOT // direct children of "root". Therefore, the "root" node has // 7 direct children System.DebugLog("NumChildren = " + Str(xml.NumChildren)) // Iterate over the direct children by index. The first child // is at index 0. Dim i As Int32 For i = 0 To xml.NumChildren - 1 // access the tag and content directly by index: System.DebugLog(Str(i) + ": " + xml.GetChildTagByIndex(i) + " : " + xml.GetChildContentByIndex(i)) Next System.DebugLog("-----") // Do the same as the above loop, but get the child node // and access the Tag and Content properties: For i = 0 To xml.NumChildren - 1 child = xml.GetChild(i) System.DebugLog(Str(i) + ": " + child.Tag + " : " + child.Content) Next System.DebugLog("-----") // Do the same as the above loop, but instead of creating // a new object instance for each child, call GetChild2 to // update the object's reference instead. For i = 0 To xml.NumChildren - 1 // Navigate to the Nth child. success = xml.GetChild2(i) System.DebugLog(Str(i) + ": " + xml.Tag + " : " + xml.Content) // Navigate back up to the parent: success = xml.GetParent2() Next System.DebugLog("-----") // Examine the result: System.DebugLog(xml.GetXml()) |
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