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(Xojo Plugin) Find XML Element where Attribute = ValueSee more XML ExamplesFinds an XML element at a particular location where an attribute has a specified value.
// We have the following XML and wish to find the value of the time attribute where msg = "alert-from". // <cdr id="4e5d3e7f41bf6201ad81000c29703270" e164="6207"> // <user> // <grp name="wfln" mode="active"/> // </user> // <event msg="setup-to" time="287069" e164="5034"/> // <event msg="alert-from" time="287069" e164="5034"/> // <event msg="rel-to" time="287079" e164="5034"/> // </cdr> Dim success As Boolean // First, build the above XML: Dim xml As New Chilkat.Xml xml.Tag = "cdr" success = xml.AddAttribute("id","4e5d3e7f41bf6201ad81000c29703270") success = xml.AddAttribute("e164","6207") success = xml.UpdateAttrAt("user|grp",True,"name","wfln") success = xml.UpdateAttrAt("user|grp",True,"mode","active") success = xml.UpdateAttrAt("event",True,"msg","setup-to") success = xml.UpdateAttrAt("event",True,"time","287069") success = xml.UpdateAttrAt("event",True,"e164","5034") success = xml.UpdateAttrAt("event[1]",True,"msg","alert-from") success = xml.UpdateAttrAt("event[1]",True,"time","287069") success = xml.UpdateAttrAt("event[1]",True,"e164","5034") success = xml.UpdateAttrAt("event[2]",True,"msg","rel-to") success = xml.UpdateAttrAt("event[2]",True,"time","287079") success = xml.UpdateAttrAt("event[2]",True,"e164","5034") // Show that we have the above XML System.DebugLog(xml.GetXml()) // Find the element where msg = "alert-from" // This updates the xml object's reference to the found element (if successful). Dim notUsed As String notUsed = xml.ChilkatPath("/A/event,msg,alert-from|$") If (xml.LastMethodSuccess = False) Then System.DebugLog("Not found.") Return End If // Get the value of the "time" attribute. System.DebugLog("time = " + xml.GetAttrValue("time")) // Restore the xml object's internal reference to the root of the XML document xml.GetRoot2 |
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