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(Xojo Plugin) Duplicate PHP RSA EncryptionDemonstrates how to duplicate the following PHP function.
// This example requires the Chilkat API to have been previously unlocked. // See Global Unlock Sample for sample code. // Duplicate the following PHP code: // // public function encryptRSA($plainText,$rsaMOD,$pubKEY){ // $rsa = new RSA(); // $rsa->setEncryptionMode(RSA::ENCRYPTION_PKCS1); // $publicKey = [ // 'e' => new BigInteger($pubKEY,16), // 'n' => new BigInteger($rsaMOD,16) // ]; // // $rsa->loadKey($publicKey); // $ciphertext = $rsa->encrypt($plainText); // return bin2hex($ciphertext); // } // // $plainText="key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678" // $rsaMOD="F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673" // $pubKEY="010001" // We have the RSA modulus in hex Dim rsaMOD As String rsaMOD = "F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673" // The RSA exponent in hex is "010001", which is 65537 in decimal. It's typically the exponent that is always used. Dim rsaEXP As String rsaEXP = "010001" // Get the RSA modulus and exponent in base64. Dim bdMod As New Chilkat.BinData Dim bdExp As New Chilkat.BinData Dim success As Boolean success = bdMod.AppendEncoded(rsaMOD,"hex") success = bdExp.AppendEncoded(rsaEXP,"hex") // Build the XML representation of the RSA public key Dim xml As New Chilkat.Xml xml.Tag = "RSAPublicKey" xml.UpdateChildContent "Modulus",bdMod.GetEncoded("base64") xml.UpdateChildContent "Exponent",bdExp.GetEncoded("base64") // Load the RSA public key into a Chilkat public key object. Dim pubkey As New Chilkat.PublicKey success = pubkey.LoadFromString(xml.GetXml()) // Setup the RSA object for encryption and do it.. Dim rsa As New Chilkat.Rsa rsa.VerboseLogging = True success = rsa.ImportPublicKeyObj(pubkey) // Use PKCSv1.5 padding rsa.OaepPadding = False // Encrypt and return the string as hex. rsa.EncodingMode = "hex" Dim plainText As String plainText = "key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678" Dim cipherText As String cipherText = rsa.EncryptStringENC(plainText,False) If (rsa.LastMethodSuccess = False) Then System.DebugLog(rsa.LastErrorText) Return End If // Note: The PKCSv1_5 padding incorporates random bytes. Therefore, the RSA encryption will produce different results each time -- all of which are valid // and decrypt correctly to the same original text. System.DebugLog(cipherText) |
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