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(VBScript) Unzip Encrypted Text into a String VariableDemonstrates how to open an encrypted .zip archive and unzip a text file directly into a string variable.
Dim fso, outFile Set fso = CreateObject("Scripting.FileSystemObject") 'Create a Unicode (utf-16) output text file. Set outFile = fso.CreateTextFile("output.txt", True, True) ' This example requires the Chilkat API to have been previously unlocked. ' See Global Unlock Sample for sample code. ' For versions of Chilkat < 10.0.0, use CreateObject("Chilkat_9_5_0.Zip") set zip = CreateObject("Chilkat.Zip") ' Set the password required for decrypting. zip.DecryptPassword = "myPassword" success = zip.OpenZip("encrypted.zip") If (success <> 1) Then outFile.WriteLine(zip.LastErrorText) WScript.Quit End If ' Locate the file within the Zip to be unzipped into a string variable: ' entry is a Chilkat.ZipEntry Set entry = zip.FirstMatchingEntry("*.csv") If (zip.LastMethodSuccess = 0) Then outFile.WriteLine("No matching entry found.") WScript.Quit End If ' lineEndingBehavior: ' 0 = leave unchanged. ' 1 = convert all to bare LF's ' 2 = convert all to CRLF's lineEndingBehavior = 0 srcCharset = "utf-8" strCsv = entry.UnzipToString(lineEndingBehavior,srcCharset) outFile.WriteLine(strCsv) outFile.Close |
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