Chilkat HOME .NET Core C# Android™ AutoIt C C# C++ Chilkat2-Python CkPython Classic ASP DataFlex Delphi ActiveX Delphi DLL Go Java Lianja Mono C# Node.js Objective-C PHP ActiveX PHP Extension Perl PowerBuilder PowerShell PureBasic Ruby SQL Server Swift 2 Swift 3,4,5... Tcl Unicode C Unicode C++ VB.NET VBScript Visual Basic 6.0 Visual FoxPro Xojo Plugin
(VBScript) Iterate over Direct Child Nodes by IndexDemonstrates some ways to iterate over direct child nodes by index. The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this: <root> <fruit color="red">apple</fruit> <fruit color="green">pear</fruit> <veg color="orange">carrot</veg> <meat animal="cow">beef</meat> <xyz> <fruit color="blue">blueberry</fruit> <veg color="green">broccoli</veg> </xyz> <fruit color="purple">grape</fruit> <cheese color="yellow">cheddar</cheese> </root>
Dim fso, outFile Set fso = CreateObject("Scripting.FileSystemObject") 'Create a Unicode (utf-16) output text file. Set outFile = fso.CreateTextFile("output.txt", True, True) ' For versions of Chilkat < 10.0.0, use CreateObject("Chilkat_9_5_0.Xml") set xml = CreateObject("Chilkat.Xml") ' The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml success = xml.LoadXmlFile("get_child.xml") If (success <> 1) Then outFile.WriteLine(xml.LastErrorText) WScript.Quit End If ' The NumChildren property contains the number of direct ' child nodes. Note: The child nodes under "xyz" are NOT ' direct children of "root". Therefore, the "root" node has ' 7 direct children outFile.WriteLine("NumChildren = " & xml.NumChildren) ' Iterate over the direct children by index. The first child ' is at index 0. For i = 0 To xml.NumChildren - 1 ' access the tag and content directly by index: outFile.WriteLine(i & ": " & xml.GetChildTagByIndex(i) & " : " & xml.GetChildContentByIndex(i)) Next outFile.WriteLine("-----") ' Do the same as the above loop, but get the child node ' and access the Tag and Content properties: For i = 0 To xml.NumChildren - 1 ' child is a Chilkat.Xml Set child = xml.GetChild(i) outFile.WriteLine(i & ": " & child.Tag & " : " & child.Content) Next outFile.WriteLine("-----") ' Do the same as the above loop, but instead of creating ' a new object instance for each child, call GetChild2 to ' update the object's reference instead. For i = 0 To xml.NumChildren - 1 ' Navigate to the Nth child. success = xml.GetChild2(i) outFile.WriteLine(i & ": " & xml.Tag & " : " & xml.Content) ' Navigate back up to the parent: success = xml.GetParent2() Next outFile.WriteLine("-----") ' Notice that the Content of the "xyz" node is empty. This is correct. ' The "xyz" node has no Content, but 2 direct children outFile.Close |
© 2000-2024 Chilkat Software, Inc. All Rights Reserved.