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(VBScript) Unzip Files to Byte ArrayDemonstrates how to unzip each file contained in a .zip to an in-memory byte array.
Dim fso, outFile Set fso = CreateObject("Scripting.FileSystemObject") 'Create a Unicode (utf-16) output text file. Set outFile = fso.CreateTextFile("output.txt", True, True) ' This example assumes the Chilkat API to have been previously unlocked. ' See Global Unlock Sample for sample code. ' For versions of Chilkat < 10.0.0, use CreateObject("Chilkat_9_5_0.Zip") set zip = CreateObject("Chilkat.Zip") success = zip.OpenZip("qa_data/zips/test.zip") If (success = 0) Then outFile.WriteLine(zip.LastErrorText) WScript.Quit End If ' Iterate of each entry in the zip. ' An entry can be a file or directory entry. For each file, unzip to a byte array. numEntries = zip.NumEntries outFile.WriteLine("NumEntries = " & numEntries) i = 0 Do While i < numEntries ' entry is a Chilkat.ZipEntry Set entry = zip.GetEntryByIndex(i) If (entry.IsDirectory = 0) Then fileData = entry.Inflate() ' Do whatever you wish with the file data... End If i = i + 1 Loop zip.CloseZip outFile.WriteLine("Finished.") outFile.Close |
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