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(VBScript) Duplicate SQL Server ENCRYPTBYPASSPHRASESee more Encryption ExamplesDemonstrates how to duplicate SQL Server's ENCRYPTBYPASSPHRASE.
Dim fso, outFile Set fso = CreateObject("Scripting.FileSystemObject") 'Create a Unicode (utf-16) output text file. Set outFile = fso.CreateTextFile("output.txt", True, True) ' This example requires the Chilkat API to have been previously unlocked. ' See Global Unlock Sample for sample code. ' For SQL Server 2008 - SQL Server 2016 we must use TripleDES with SHA1 ' For SQL Server 2017 and later, use AES256 / SHA256. password = "tEst1234" encryptedHex_v1 = "0x010000001E8E7DCDBD4061B951999E25D18445D2305474D2D71EEE98A241C755246F58AB" ' Here's an encrypted string using AES256/SHA256 encryptedHex_v2 = "0x02000000FFE880C0354780481E64EF25B6197A02E2A854A4BA9D8D9BDDFDAB27EB56537ABDA0B1D9C4D1050C91B313550DECF429" ' For versions of Chilkat < 10.0.0, use CreateObject("Chilkat_9_5_0.StringBuilder") set sbEncHex = CreateObject("Chilkat.StringBuilder") success = sbEncHex.Append(encryptedHex_v1) ' If present, we don't want the leading "0x" If (sbEncHex.StartsWith("0x",0) = 1) Then success = sbEncHex.RemoveCharsAt(0,2) End If ' For versions of Chilkat < 10.0.0, use CreateObject("Chilkat_9_5_0.Crypt2") set crypt = CreateObject("Chilkat.Crypt2") crypt.EncodingMode = "hex" ' The encrypted hex string will begin with either 01000000 or 02000000 ' version 1 is produced by SQL Server 2008 to SQL Server 2016, and we must use TripleDES with SHA1 ' version 2 is for SQL Server 2017 and later, and uses AES256 / SHA256. v1 = sbEncHex.StartsWith("01",0) ivLen = 0 If (v1 = 1) Then crypt.CryptAlgorithm = "3des" crypt.CipherMode = "cbc" crypt.KeyLength = 168 ivLen = 8 hashAlg = "sha1" Else crypt.CryptAlgorithm = "aes" crypt.CipherMode = "cbc" crypt.KeyLength = 256 ivLen = 16 hashAlg = "sha256" End If ' Remove the SQL Server version info (i.e. the "01000000") success = sbEncHex.RemoveCharsAt(0,8) ' Get the IV part of the sbEncHex, and also remove it from the StringBuilder. ivHex = sbEncHex.GetRange(0,ivLen * 2,1) outFile.WriteLine("IV = " & ivHex) crypt.SetEncodedIV ivHex,"hex" ' For versions of Chilkat < 10.0.0, use CreateObject("Chilkat_9_5_0.StringBuilder") set sbPassword = CreateObject("Chilkat.StringBuilder") success = sbPassword.Append(password) pwd_hash = sbPassword.GetHash(hashAlg,"hex","utf-16") ' For versions of Chilkat < 10.0.0, use CreateObject("Chilkat_9_5_0.StringBuilder") set sbKey = CreateObject("Chilkat.StringBuilder") success = sbKey.Append(pwd_hash) If (v1 = 1) Then ' For v1, we only want the 1st 16 bytes of the 20 byte hash. ' (remember, the hex encoding uses 2 chars per byte, so we remove the last 8 chars) success = sbKey.Shorten(8) End If outFile.WriteLine("crypt key: " & sbKey.GetAsString()) crypt.SetEncodedKey sbKey.GetAsString(),"hex" ' Decrypt ' For versions of Chilkat < 10.0.0, use CreateObject("Chilkat_9_5_0.BinData") set bd = CreateObject("Chilkat.BinData") success = bd.AppendEncoded(sbEncHex.GetAsString(),"hex") success = crypt.DecryptBd(bd) ' The result is composed of a header of 8 bytes which we can discard. ' The remainder is the decrypted text. ' The header we are discarding is composed of: ' Bytes 0-3: Magic number equal to 0DF0ADBA ' Bytes 4-5: Number of integrity bytes, which is 0 unless an authenticator is used. We're assuming no authenticator is used. ' Bytes 6-7: Number of plain-text bytes. We really don't need this because the CBC padding takes care of it. ' Therefore, just return the data after the 1st 8 bytes. ' Assuming the encrypted string was utf-8 text... success = bd.RemoveChunk(0,8) plainText = bd.GetString("utf-8") outFile.WriteLine("decrypted plain text: " & plainText) ' The output: ' IV = 1E8E7DCDBD4061B9 ' crypt key: 710B9C2E61ACCC9570D4112203BD9738 ' decrypted plain text: Hello world. ' ------------------------------------------------------------------------------------------ ' To encrypt, do the reverse... ' Let's do v1 with TripleDES with SHA1 ' For versions of Chilkat < 10.0.0, use CreateObject("Chilkat_9_5_0.Crypt2") set encryptor = CreateObject("Chilkat.Crypt2") encryptor.EncodingMode = "hex" encryptor.CryptAlgorithm = "3des" encryptor.CipherMode = "cbc" encryptor.KeyLength = 168 ' Generate a random 8-byte IV ' For versions of Chilkat < 10.0.0, use CreateObject("Chilkat_9_5_0.Prng") set prng = CreateObject("Chilkat.Prng") ivHex = prng.GenRandom(8,"hex") encryptor.SetEncodedIV ivHex,"hex" ' The binary password is generated the same as above. ' We'll use the same password (and same binary password) encryptor.SetEncodedKey sbKey.GetAsString(),"hex" plainTextLen = 8 plainText = "ABCD1234" ' Encrypt the header + the plain-text. ' For versions of Chilkat < 10.0.0, use CreateObject("Chilkat_9_5_0.BinData") set bdData = CreateObject("Chilkat.BinData") success = bdData.AppendEncoded("0DF0ADBA","hex") success = bdData.AppendEncoded("0000","hex") success = bdData.AppendInt2(plainTextLen,1) outFile.WriteLine("header: " & bdData.GetEncoded("hex")) success = bdData.AppendString(plainText,"utf-8") success = encryptor.EncryptBd(bdData) ' Compose the result.. ' For versions of Chilkat < 10.0.0, use CreateObject("Chilkat_9_5_0.StringBuilder") set sbEnc = CreateObject("Chilkat.StringBuilder") success = sbEnc.Append("0x01000000") success = sbEnc.Append(ivHex) success = sbEnc.Append(bdData.GetEncoded("hex")) outFile.WriteLine("result: " & sbEnc.GetAsString()) outFile.Close |
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