VBScript

Box.com Upload File

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Demonstrates how to upload a file to box.com. VBScript

Dim fso, outFile
Set fso = CreateObject("Scripting.FileSystemObject")
'Create a Unicode (utf-16) output text file.
Set outFile = fso.CreateTextFile("output.txt", True, True)

success = 0

' This requires the Chilkat API to have been previously unlocked.
' See Global Unlock Sample for sample code.

' ------------------------------------------------------------------------------------------
' Important:
' See this information about Box.com Service Accounts
' Box.com will automatically generate a Service Account where the name of the account is the name of your App.� 
' When you make API calls, it is for this service account, and the files that exist and what you see are not the same as your normal account.
' ------------------------------------------------------------------------------------------

set rest = CreateObject("Chilkat.Rest")

'   Provide a previously obtained OAuth2 access token.
set oauth2 = CreateObject("Chilkat.OAuth2")
oauth2.AccessToken = "BOX_ACCESS_TOKEN"
success = rest.SetAuthOAuth2(oauth2)

' First, make the initial connection.
' A single REST object, once connected, can be used for many Box REST API calls.
' The auto-reconnect indicates that if the already-established HTTPS connection is closed,
' then it will be automatically re-established as needed.
bAutoReconnect = 1

' ----------------------------------------------------------------------
' IMPORTANT: Note that the domain is "upload.box.com", not "api.box.com"
' ----------------------------------------------------------------------
success = rest.Connect("upload.box.com",443,1,bAutoReconnect)
If (success <> 1) Then
    outFile.WriteLine(rest.LastErrorText)
    WScript.Quit
End If

' The request body uses the "multipart/form-data" format to transmit two "parts". 
' The first part is called "attributes" and contains a JSON object with information about the file, including the name of the file 
' and the ID of the parent folder. The second part contains the contents of the file. 
' (Note that the name of the second "part" is ignored.)

success = rest.AddHeader("Content-Type","multipart/form-data")

' Provide the content for each part of the request...

' First the JSON attributes.  Use "0" for the root folder.
'   {"name":"penguins.jpg", "parent":{"id":"0"}}
set jsonAttr = CreateObject("Chilkat.JsonObject")
success = jsonAttr.UpdateString("name","penguins.jpg")
success = jsonAttr.UpdateString("parent.id","0")

rest.PartSelector = "1"
success = rest.AddHeader("Content-Disposition","form-data; name=""attributes""; ")
success = rest.SetMultipartBodyString(jsonAttr.Emit())

rest.PartSelector = "2"
success = rest.AddHeader("Content-Disposition","form-data; name=""file""; filename=""penguins.jpg""")
' "application/octet-stream" can be safely used for any type file..
success = rest.AddHeader("Content-Type","application/octet-stream")

' Load the file into a binary data object, and then upload..
set fileDataObj = CreateObject("Chilkat.BinData")
success = fileDataObj.LoadFile("qa_data/jpg/penguins.jpg")
success = rest.SetMultipartBodyBd(fileDataObj)

' Restore the PartSelector to "0" (for safety, in case something else sends another request on this object)
rest.PartSelector = "0"

' Send the multipart/form-data request, which uploads the file contained in fileDataObj
responseBody = rest.FullRequestMultipart("POST","/api/2.0/files/content")
If (rest.LastMethodSuccess <> 1) Then
    outFile.WriteLine(rest.LastErrorText)
    WScript.Quit
End If

' A 201 is received for a successful upload
If (rest.ResponseStatusCode <> 201) Then
    outFile.WriteLine("Box.com upload failed.")
    outFile.WriteLine("Request header:")
    outFile.WriteLine(rest.LastRequestHeader)
    outFile.WriteLine("---")
    outFile.WriteLine("Response status code = " & rest.ResponseStatusCode)
    outFile.WriteLine("Response body:")
    outFile.WriteLine(responseBody)
    WScript.Quit
End If

outFile.WriteLine("File uploaded.")

outFile.Close