VB.NET

Parsing XML Children Having Identical Tags

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Demonstrates how to deal with XML where child elements may have identical tags. VB.NET

Dim success As Boolean = False

' This example will get the phoneNumber's and groupMembershihpInfo's from the following XML:

' <?xml version="1.0" encoding="UTF-8" ?>
' <someEntries>
'     <entry>
'         <id>123</id>
'         <updated>2017-07-19T05:19:57.761Z</updated>
'         <app:edited xmlns:app="http://www.w3.org/2007/app">2017-07-19T05:19:57.761Z</app:edited>
'         <category scheme="http://schemas.google.com/g/2005#kind" term="http://schemas.google.com/contact/2008#contact"/>
'         <title>George Costanza</title>
'          <gd:name>
'             <gd:fullName>George Costanza</gd:fullName>
'             <gd:givenName>George</gd:givenName>
'             <gd:familyName>Costanza</gd:familyName>
'         </gd:name>
'         <gd:phoneNumber rel="http://schemas.google.com/g/2005#home">(555) 123-4567</gd:phoneNumber>
'         <gd:phoneNumber rel="http://schemas.google.com/g/2005#mobile">(555) 444-8877</gd:phoneNumber>
'         <gd:phoneNumber rel="http://schemas.google.com/g/2005#work">(555) 678-1111</gd:phoneNumber>
'         <gContact:groupMembershipInfo deleted="false" href="http://www.google.com/123"/>
'         <gContact:groupMembershipInfo deleted="false" href="http://www.google.com/456"/>
'     </entry>
' </someEntries>
' 

Dim xml As New Chilkat.Xml

success = xml.LoadXmlFile("qa_data/xml/georgeCostanza.xml")

Dim numPhoneNumbers As Integer = xml.NumChildrenHavingTag("entry|*:phoneNumber")
Dim i As Integer = 0
While i < numPhoneNumbers
    Dim xPhoneNumber As Chilkat.Xml = xml.GetNthChildWithTag("entry|*:phoneNumber",i)
    Debug.WriteLine(xPhoneNumber.Content)

    i = i + 1
End While
Debug.WriteLine("----")

Dim numGroupMemberships As Integer = xml.NumChildrenHavingTag("entry|*:groupMembershipInfo")
i = 0
While i < numGroupMemberships
    Dim xMembership As Chilkat.Xml = xml.GetNthChildWithTag("entry|*:groupMembershipInfo",i)
    Debug.WriteLine(xMembership.GetAttrValue("href"))

    i = i + 1
End While