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(Unicode C++) Iterate over Direct Children with a Specific TagDemonstrates how to iterate over direct children having a specific tag. The input XML, available at http://www.chilkatsoft.com/data/fruit.xml, is this: <root> <fruit color="red">apple</fruit> <fruit color="green">pear</fruit> <veg color="orange">carrot</veg> <meat animal="cow">beef</meat> <xyz> <fruit color="blue">blueberry</fruit> <veg color="green">broccoli</veg> </xyz> <fruit color="purple">grape</fruit> <cheese color="yellow">cheddar</cheese> </root>
#include <CkXmlW.h> void ChilkatSample(void) { CkXmlW xml; CkXmlW *child = 0; int numWithTag; int i; bool success; // The sample input XML is available at http://www.chilkatsoft.com/data/fruit.xml success = xml.LoadXmlFile(L"fruit.xml"); if (success != true) { wprintf(L"%s\n",xml.lastErrorText()); return; } // Get the number of direct children having the tag "fruit" numWithTag = xml.NumChildrenHavingTag(L"fruit"); if (numWithTag > 0) { for (i = 0; i <= numWithTag - 1; i++) { child = xml.GetNthChildWithTag(L"fruit",i); wprintf(L"%d: %s : %s\n",i,child->tag(),child->content()); delete child; } wprintf(L"-----\n"); // Do the same as the above loop, but instead of creating // a new object instance for each child, call GetNthChildWithTag2 to // update the object's reference instead. for (i = 0; i <= numWithTag - 1; i++) { // Navigate to the Nth child. success = xml.GetNthChildWithTag2(L"fruit",i); wprintf(L"%d: %s : %s\n",i,xml.tag(),xml.content()); // Navigate back up to the parent: success = xml.GetParent2(); } wprintf(L"-----\n"); } } |
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