(Unicode C++) Parse Multipart Binary Http Response

This example demonstrates how to parse an HTTP response that is multipart and contains a binary file, such as a .zip or .pdf.

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#include <CkHttpW.h>
#include <CkHttpRequestW.h>
#include <CkHttpResponseW.h>
#include <CkBinDataW.h>
#include <CkMimeW.h>

void ChilkatSample(void)
    {
    // This example requires the Chilkat API to have been previously unlocked.
    // See Global Unlock Sample for sample code.

    bool success;
    CkHttpW http;

    CkHttpRequestW req;

    // ...
    // Insert code here to construct some kind of HTTP request.
    // this example is to show how to parse a particular kind of response.
    // ...
    // ...

    // Send the request (whatever it may be in your case) to get the HTTP response object.
    CkHttpResponseW *resp = http.SynchronousRequest(L"www.somedomain.com",443,true,req);
    if (http.get_LastMethodSuccess() != true) {
        wprintf(L"%s\n",http.lastErrorText());
        return;
    }

    // Get the response body (which is expected to be binary)
    CkBinDataW respBody;
    resp->GetBodyBd(respBody);
    delete resp;

    // For this example, the response body contains something like this:

    // ------=_Part_21302_2029949381.1547401515443
    // Content-Type: application/xop+xml; charset=UTF-8; type="text/xml"
    // Content-Transfer-Encoding: 8bit
    // Content-ID: <rootpart@ws.jboss.org>
    // 
    // <env:Envelope xmlns:env='http://schemas.xmlsoap.org/soap/envelope/'><env:Header></env:Header><env:Body>...</env:Body></env:Envelope>
    // ------=_Part_21302_2029949381.1547401515443
    // Content-Type: application/octet-stream
    // Content-Transfer-Encoding: binary
    // Content-Id: <fileArchivio-7d302908-4d64-43d3-bf4e-79ce806d43b3@ws.jboss.org>
    // 
    // BINARY_CONTENT_HERE...
    // 
    // ------=_Part_21302_2029949381.1547401515443--
    // 

    // Load it into a Chilkat MIME object.
    CkMimeW mime;
    success = mime.LoadMimeBd(respBody);
    if (success != true) {
        wprintf(L"%s\n",mime.lastErrorText());
        return;
    }

    int numParts = mime.get_NumParts();
    if (numParts < 2) {
        wprintf(L"Expected multipart MIME with at least 2 sub-parts.\n");
        return;
    }

    // Get the 1st sub-part, which is the XML.
    CkMimeW *part0 = mime.GetPart(0);
    // Should be OK because we checked NumParts above..
    const wchar_t *xmlStr = part0->getBodyDecoded();
    wprintf(L"%s\n",xmlStr);
    wprintf(L"----\n");
    delete part0;

    // Save the 2nd part to a file.  (It is a .zip file in our test case..)
    CkMimeW *part1 = mime.GetPart(1);
    success = part1->SaveBody(L"qa_output/attachedZip.zip");

    // Alternatively, we could extract the binary data to a BinData and use elsewhere..
    CkBinDataW zipData;
    success = part1->GetBodyBd(zipData);
    success = zipData.WriteFile(L"qa_output/attachedZip_again.zip");
    delete part1;

    wprintf(L"OK.\n");
    }