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(Unicode C++) Traverse Direct Children via FirstChild / NextSibling, or LastChild / PreviousSiblingDemonstrates some ways to iterate over direct child nodes using the FirstChild / NextSibling and LastChild / PreviousSibling methods. The input XML, available at http://www.chilkatsoft.com/data/fruit.xml, is this:
<root>
<fruit color="red">apple</fruit>
<fruit color="green">pear</fruit>
<veg color="orange">carrot</veg>
<meat animal="cow">beef</meat>
<xyz>
<fruit color="blue">blueberry</fruit>
<veg color="green">broccoli</veg>
</xyz>
<fruit color="purple">grape</fruit>
<cheese color="yellow">cheddar</cheese>
</root>
#include <CkXmlW.h> void ChilkatSample(void) { CkXmlW xml; CkXmlW *child = 0; CkXmlW *nextSibling = 0; CkXmlW *prevSibling = 0; bool success = xml.LoadXmlFile(L"qa_data/xml/fruit.xml"); if (success != true) { wprintf(L"%s\n",xml.lastErrorText()); return; } // Iterate over the direct children by using FirstChild / NextSibling child = xml.FirstChild(); bool bContinue = xml.get_LastMethodSuccess(); while ((bContinue == true)) { wprintf(L"%s : %s\n",child->tag(),child->content()); nextSibling = child->NextSibling(); bContinue = child->get_LastMethodSuccess(); delete child; child = nextSibling; } wprintf(L"-----\n"); // Do the same, but with FirstChild2 / NextSibling2 to avoid // creating so many XML object instances: success = xml.FirstChild2(); while (success == true) { wprintf(L"%s : %s\n",xml.tag(),xml.content()); success = xml.NextSibling2(); } // Revert back up to the parent: success = xml.GetParent2(); wprintf(L"-----\n"); // Iterate in reverse order using LastChild / PreviousSibling child = xml.LastChild(); bContinue = xml.get_LastMethodSuccess(); while ((bContinue == true)) { wprintf(L"%s : %s\n",child->tag(),child->content()); prevSibling = child->PreviousSibling(); bContinue = child->get_LastMethodSuccess(); delete child; child = prevSibling; } wprintf(L"-----\n"); // Do the same, but with LastChild2 / PreviousSibling2 to avoid // creating so many XML object instances: success = xml.LastChild2(); while (success == true) { wprintf(L"%s : %s\n",xml.tag(),xml.content()); success = xml.PreviousSibling2(); } // Revert back up to the parent: success = xml.GetParent2(); } |
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