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(Unicode C++) Traverse Direct Children via FirstChild / NextSibling, or LastChild / PreviousSiblingDemonstrates some ways to iterate over direct child nodes using the FirstChild / NextSibling and LastChild / PreviousSibling methods. The input XML, available at http://www.chilkatsoft.com/data/fruit.xml, is this: <root> <fruit color="red">apple</fruit> <fruit color="green">pear</fruit> <veg color="orange">carrot</veg> <meat animal="cow">beef</meat> <xyz> <fruit color="blue">blueberry</fruit> <veg color="green">broccoli</veg> </xyz> <fruit color="purple">grape</fruit> <cheese color="yellow">cheddar</cheese> </root>
#include <CkXmlW.h> void ChilkatSample(void) { CkXmlW xml; CkXmlW *child = 0; CkXmlW *nextSibling = 0; CkXmlW *prevSibling = 0; bool success = xml.LoadXmlFile(L"qa_data/xml/fruit.xml"); if (success != true) { wprintf(L"%s\n",xml.lastErrorText()); return; } // Iterate over the direct children by using FirstChild / NextSibling child = xml.FirstChild(); bool bContinue = xml.get_LastMethodSuccess(); while ((bContinue == true)) { wprintf(L"%s : %s\n",child->tag(),child->content()); nextSibling = child->NextSibling(); bContinue = child->get_LastMethodSuccess(); delete child; child = nextSibling; } wprintf(L"-----\n"); // Do the same, but with FirstChild2 / NextSibling2 to avoid // creating so many XML object instances: success = xml.FirstChild2(); while (success == true) { wprintf(L"%s : %s\n",xml.tag(),xml.content()); success = xml.NextSibling2(); } // Revert back up to the parent: success = xml.GetParent2(); wprintf(L"-----\n"); // Iterate in reverse order using LastChild / PreviousSibling child = xml.LastChild(); bContinue = xml.get_LastMethodSuccess(); while ((bContinue == true)) { wprintf(L"%s : %s\n",child->tag(),child->content()); prevSibling = child->PreviousSibling(); bContinue = child->get_LastMethodSuccess(); delete child; child = prevSibling; } wprintf(L"-----\n"); // Do the same, but with LastChild2 / PreviousSibling2 to avoid // creating so many XML object instances: success = xml.LastChild2(); while (success == true) { wprintf(L"%s : %s\n",xml.tag(),xml.content()); success = xml.PreviousSibling2(); } // Revert back up to the parent: success = xml.GetParent2(); } |
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