Sample code for 30+ languages & platforms
Unicode C++

Iterate over Direct Children with a Specific Tag

See more XML Examples

Demonstrates how to iterate over direct children having a specific tag.

The input XML, available at http://www.chilkatsoft.com/data/fruit.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Chilkat Unicode C++ Downloads

Unicode C++
#include <CkXmlW.h>

void ChilkatSample(void)
    {
    bool success = false;

    CkXmlW xml;
    CkXmlW *child = 0;
    int numWithTag;
    int i;

    // The sample input XML is available at http://www.chilkatsoft.com/data/fruit.xml
    success = xml.LoadXmlFile(L"fruit.xml");
    if (success != true) {
        wprintf(L"%s\n",xml.lastErrorText());
        return;
    }

    //  Get the number of direct children having the tag "fruit"
    numWithTag = xml.NumChildrenHavingTag(L"fruit");

    if (numWithTag > 0) {

        for (i = 0; i <= numWithTag - 1; i++) {
            child = xml.GetNthChildWithTag(L"fruit",i);
            wprintf(L"%d: %s : %s\n",i,child->tag(),child->content());
            delete child;
        }

        wprintf(L"-----\n");

        // Do the same as the above loop, but instead of creating
        // a new object instance for each child, call GetNthChildWithTag2 to
        // update the object's reference instead.
        for (i = 0; i <= numWithTag - 1; i++) {
            // Navigate to the Nth child.  
            success = xml.GetNthChildWithTag2(L"fruit",i);
            wprintf(L"%d: %s : %s\n",i,xml.tag(),xml.content());
            // Navigate back up to the parent:
            success = xml.GetParent2();
        }

        wprintf(L"-----\n");
    }
    }