Unicode C++

GetChild* methods

See more XML Examples

Demonstrates several of the GetChild* methods.

The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

The output XML is this:

<abc b="pear" c="orange" a="130">Test</abc>

Unicode C++

#include <CkXmlW.h>

void ChilkatSample(void)
    {
    bool success = false;

    CkXmlW xml;
    CkXmlW *child = 0;

    // The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
    success = xml.LoadXmlFile(L"get_child.xml");
    if (success != true) {
        wprintf(L"%s\n",xml.lastErrorText());
        return;
    }

    // The NumChildren property contains the number of direct
    // child nodes.  Note: The child nodes under "xyz" are NOT
    // direct children of "root".  Therefore, the "root" node has
    // 7 direct children
    wprintf(L"NumChildren = %d\n",xml.get_NumChildren());

    // Iterate over the direct children by index. The first child
    // is at index 0.
    int i;
    for (i = 0; i <= xml.get_NumChildren() - 1; i++) {
        //  access the tag and content directly by index:
        wprintf(L"%d: %s : %s\n",i,xml.getChildTagByIndex(i),xml.getChildContentByIndex(i));

    }

    wprintf(L"-----\n");

    // Do the same as the above loop, but get the child node
    // and access the Tag and Content properties:
    for (i = 0; i <= xml.get_NumChildren() - 1; i++) {
        child = xml.GetChild(i);
        wprintf(L"%d: %s : %s\n",i,child->tag(),child->content());
        delete child;
    }

    wprintf(L"-----\n");

    // Do the same as the above loop, but instead of creating
    // a new object instance for each child, call GetChild2 to
    // update the object's reference instead.
    for (i = 0; i <= xml.get_NumChildren() - 1; i++) {
        // Navigate to the Nth child.  
        success = xml.GetChild2(i);
        wprintf(L"%d: %s : %s\n",i,xml.tag(),xml.content());
        // Navigate back up to the parent:
        success = xml.GetParent2();
    }

    wprintf(L"-----\n");

    // Examine the result:
    wprintf(L"%s\n",xml.getXml());
    }