Unicode C++

Parse Multipart Binary Http Response

See more HTTP Examples

This example demonstrates how to parse an HTTP response that is multipart and contains a binary file, such as a .zip or .pdf. Unicode C++

#include <CkHttpW.h>
#include <CkHttpRequestW.h>
#include <CkHttpResponseW.h>
#include <CkBinDataW.h>
#include <CkMimeW.h>

void ChilkatSample(void)
    {
    bool success = false;

    // This example requires the Chilkat API to have been previously unlocked.
    // See Global Unlock Sample for sample code.

    CkHttpW http;
    CkHttpRequestW req;

    // ...
    // Insert code here to construct some kind of HTTP request.
    // this example is to show how to parse a particular kind of response.
    // ...
    // ...

    // Send the request (whatever it may be in your case) to get the HTTP response object.
    CkHttpResponseW resp;
    success = http.HttpSReq(L"www.somedomain.com",443,true,req,resp);
    if (success == false) {
        wprintf(L"%s\n",http.lastErrorText());
        return;
    }

    // Get the response body (which is expected to be binary)
    CkBinDataW respBody;
    resp.GetBodyBd(respBody);

    // For this example, the response body contains something like this:

    // ------=_Part_21302_2029949381.1547401515443
    // Content-Type: application/xop+xml; charset=UTF-8; type="text/xml"
    // Content-Transfer-Encoding: 8bit
    // Content-ID: <rootpart@ws.jboss.org>
    // 
    // <env:Envelope xmlns:env='http://schemas.xmlsoap.org/soap/envelope/'><env:Header></env:Header><env:Body>...</env:Body></env:Envelope>
    // ------=_Part_21302_2029949381.1547401515443
    // Content-Type: application/octet-stream
    // Content-Transfer-Encoding: binary
    // Content-Id: <fileArchivio-7d302908-4d64-43d3-bf4e-79ce806d43b3@ws.jboss.org>
    // 
    // BINARY_CONTENT_HERE...
    // 
    // ------=_Part_21302_2029949381.1547401515443--
    // 

    // Load it into a Chilkat MIME object.
    CkMimeW mime;
    success = mime.LoadMimeBd(respBody);
    if (success == false) {
        wprintf(L"%s\n",mime.lastErrorText());
        return;
    }

    int numParts = mime.get_NumParts();
    if (numParts < 2) {
        wprintf(L"Expected multipart MIME with at least 2 sub-parts.\n");
        return;
    }

    // Get the 1st sub-part, which is the XML.

    CkMimeW part0;
    mime.PartAt(0,part0);

    // Should be OK because we checked NumParts above..
    const wchar_t *xmlStr = part0.getBodyDecoded();
    wprintf(L"%s\n",xmlStr);
    wprintf(L"----\n");

    // Save the 2nd part to a file.  (It is a .zip file in our test case..)

    CkMimeW part1;
    mime.PartAt(1,part1);

    success = part1.SaveBody(L"qa_output/attachedZip.zip");

    // Alternatively, we could extract the binary data to a BinData and use elsewhere..
    CkBinDataW zipData;
    success = part1.GetBodyBd(zipData);
    success = zipData.WriteFile(L"qa_output/attachedZip_again.zip");

    wprintf(L"OK.\n");
    }