(Swift 3,4,5...) Iterate over Direct Children with a Specific Tag

Demonstrates how to iterate over direct children having a specific tag.

The input XML, available at http://www.chilkatsoft.com/data/fruit.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Chilkat Downloads for the Swift Programming Language MAC OS X (Cocoa) Objective-C/Swift Libs iOS Objective-C/Swift Libs

func chilkatTest() {
    let xml = CkoXml()!
    var child: CkoXml?
    var numWithTag: Int
    var i: Int

    var success: Bool
    // The sample input XML is available at http://www.chilkatsoft.com/data/fruit.xml
    success = xml.loadFile("fruit.xml")
    if success != true {
        print("\(xml.lastErrorText!)")
        return
    }

    //  Get the number of direct children having the tag "fruit"
    numWithTag = xml.numChildrenHavingTag("fruit").intValue

    if numWithTag > 0 {

        for i = 0; i <= numWithTag - 1; i++ {
            child = xml.getNthChild(withTag: "fruit", n: i)
            print("\(i): \(child!.tag!) : \(child!.content!)")
            child = nil
        }

        print("-----")

        // Do the same as the above loop, but instead of creating
        // a new object instance for each child, call GetNthChildWithTag2 to
        // update the object's reference instead.
        for i = 0; i <= numWithTag - 1; i++ {
            // Navigate to the Nth child.  
            success = xml.getNthChild(withTag2: "fruit", n: i)
            print("\(i): \(xml.tag!) : \(xml.content!)")
            // Navigate back up to the parent:
            success = xml.getParent2()
        }

        print("-----")
    }


}