(Swift 2) Traverse Direct Children via FirstChild / NextSibling, or LastChild / PreviousSibling

Demonstrates some ways to iterate over direct child nodes using the FirstChild / NextSibling and LastChild / PreviousSibling methods.

The input XML, available at http://www.chilkatsoft.com/data/fruit.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Chilkat Downloads for the Swift Programming Language MAC OS X (Cocoa) Objective-C/Swift Libs iOS Objective-C/Swift Libs

func chilkatTest() {
    let xml = CkoXml()
    var child: CkoXml?
    var nextSibling: CkoXml?
    var prevSibling: CkoXml?

    var success: Bool = xml.LoadXmlFile("qa_data/xml/fruit.xml")
    if success != true {
        print("\(xml.LastErrorText)")
        return
    }

    // Iterate over the direct children by using FirstChild / NextSibling
    child = xml.FirstChild()
    var bContinue: Bool = xml.LastMethodSuccess
    while (bContinue == true) {
        print("\(child!.Tag) : \(child!.Content)")
        nextSibling = child!.NextSibling()
        bContinue = child!.LastMethodSuccess
        child = nil
        child = nextSibling
    }

    print("-----")

    // Do the same, but with FirstChild2 / NextSibling2 to avoid
    // creating so many XML object instances:
    success = xml.FirstChild2()
    while success == true {
        print("\(xml.Tag) : \(xml.Content)")
        success = xml.NextSibling2()
    }

    // Revert back up to the parent:
    success = xml.GetParent2()

    print("-----")

    // Iterate in reverse order using LastChild / PreviousSibling
    child = xml.LastChild()
    bContinue = xml.LastMethodSuccess
    while (bContinue == true) {
        print("\(child!.Tag) : \(child!.Content)")
        prevSibling = child!.PreviousSibling()
        bContinue = child!.LastMethodSuccess
        child = nil
        child = prevSibling
    }

    print("-----")

    // Do the same, but with LastChild2 / PreviousSibling2 to avoid
    // creating so many XML object instances:
    success = xml.LastChild2()
    while success == true {
        print("\(xml.Tag) : \(xml.Content)")
        success = xml.PreviousSibling2()
    }

    // Revert back up to the parent:
    success = xml.GetParent2()

}