Chilkat HOME .NET Core C# Android™ AutoIt C C# C++ Chilkat2-Python CkPython Classic ASP DataFlex Delphi ActiveX Delphi DLL Go Java Lianja Mono C# Node.js Objective-C PHP ActiveX PHP Extension Perl PowerBuilder PowerShell PureBasic Ruby SQL Server Swift 2 Swift 3,4,5... Tcl Unicode C Unicode C++ VB.NET VBScript Visual Basic 6.0 Visual FoxPro Xojo Plugin
(Swift 2) GetChild* methodsDemonstrates several of the GetChild* methods. The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this: <root> <fruit color="red">apple</fruit> <fruit color="green">pear</fruit> <veg color="orange">carrot</veg> <meat animal="cow">beef</meat> <xyz> <fruit color="blue">blueberry</fruit> <veg color="green">broccoli</veg> </xyz> <fruit color="purple">grape</fruit> <cheese color="yellow">cheddar</cheese> </root> The output XML is this: <abc b="pear" c="orange" a="130">Test</abc>
func chilkatTest() { let xml = CkoXml() var child: CkoXml? var success: Bool // The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml success = xml.LoadXmlFile("get_child.xml") if success != true { print("\(xml.LastErrorText)") return } // The NumChildren property contains the number of direct // child nodes. Note: The child nodes under "xyz" are NOT // direct children of "root". Therefore, the "root" node has // 7 direct children print("NumChildren = \(xml.NumChildren.intValue)") // Iterate over the direct children by index. The first child // is at index 0. var i: Int for i = 0; i <= xml.NumChildren.intValue - 1; i++ { // access the tag and content directly by index: print("\(i): \(xml.GetChildTagByIndex(i)) : \(xml.GetChildContentByIndex(i))") } print("-----") // Do the same as the above loop, but get the child node // and access the Tag and Content properties: for i = 0; i <= xml.NumChildren.intValue - 1; i++ { child = xml.GetChild(i) print("\(i): \(child!.Tag) : \(child!.Content)") child = nil } print("-----") // Do the same as the above loop, but instead of creating // a new object instance for each child, call GetChild2 to // update the object's reference instead. for i = 0; i <= xml.NumChildren.intValue - 1; i++ { // Navigate to the Nth child. success = xml.GetChild2(i) print("\(i): \(xml.Tag) : \(xml.Content)") // Navigate back up to the parent: success = xml.GetParent2() } print("-----") // Examine the result: print("\(xml.GetXml())") } |
© 2000-2024 Chilkat Software, Inc. All Rights Reserved.