Swift
Swift
S3 List Buckets (using Chilkat REST)
See more Amazon S3 (new) Examples
Demonstrates how to fetch a list of S3 buckets.Chilkat Swift Downloads
func chilkatTest() {
var success: Bool = false
// This example requires the Chilkat API to have been previously unlocked.
// See Global Unlock Sample for sample code.
let rest = CkoRest()!
// Connect to the Amazon AWS REST server.
var bTls: Bool = true
var port: Int = 443
var bAutoReconnect: Bool = true
success = rest.connect(hostname: "s3.amazonaws.com", port: port, tls: bTls, autoReconnect: bAutoReconnect)
// ----------------------------------------------------------------------------
// Important: For buckets created in regions outside us-east-1,
// there are three important changes that need to be made.
// See Working with S3 Buckets in Non-us-east-1 Regions for the details.
// ----------------------------------------------------------------------------
// Provide AWS credentials for the REST call.
let authAws = CkoAuthAws()!
authAws.accessKey = "AWS_ACCESS_KEY"
authAws.secretKey = "AWS_SECRET_KEY"
authAws.serviceName = "s3"
success = rest.setAuthAws(authProvider: authAws)
let sbResponse = CkoStringBuilder()!
success = rest.fullRequestNoBodySb(httpVerb: "GET", uriPath: "/", sb: sbResponse)
if success == false {
print("\(rest.lastErrorText!)")
return
}
var statusCode: Int = rest.responseStatusCode.intValue
print("Response status code = \(statusCode)")
let xml = CkoXml()!
xml.loadSb(sb: sbResponse, autoTrim: true)
print("\(xml.getXml()!)")
if statusCode != 200 {
print("Failed. See error information in the XML.")
return
}
// Use this online tool to generate code from sample XML:
// Generate Code to Create XML
var Name: String?
var CreationDate: String?
var i: Int = 0
var count_i: Int = xml.numChildrenHavingTag(tag: "Buckets|Bucket").intValue
while i < count_i {
xml.i = i
Name = xml.getChildContent(tagPath: "Buckets|Bucket[i]|Name")
CreationDate = xml.getChildContent(tagPath: "Buckets|Bucket[i]|CreationDate")
print("\(Name!)")
print("\(CreationDate!)")
print("--")
i = i + 1
}
}