Rust

Parsing XML Children Having Identical Tags

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Demonstrates how to deal with XML where child elements may have identical tags. Rust

// This example will get the phoneNumber's and groupMembershihpInfo's from the following XML:

// <?xml version="1.0" encoding="UTF-8" ?>
// <someEntries>
//     <entry>
//         <id>123</id>
//         <updated>2017-07-19T05:19:57.761Z</updated>
//         <app:edited xmlns:app="http://www.w3.org/2007/app">2017-07-19T05:19:57.761Z</app:edited>
//         <category scheme="http://schemas.google.com/g/2005#kind" term="http://schemas.google.com/contact/2008#contact"/>
//         <title>George Costanza</title>
//          <gd:name>
//             <gd:fullName>George Costanza</gd:fullName>
//             <gd:givenName>George</gd:givenName>
//             <gd:familyName>Costanza</gd:familyName>
//         </gd:name>
//         <gd:phoneNumber rel="http://schemas.google.com/g/2005#home">(555) 123-4567</gd:phoneNumber>
//         <gd:phoneNumber rel="http://schemas.google.com/g/2005#mobile">(555) 444-8877</gd:phoneNumber>
//         <gd:phoneNumber rel="http://schemas.google.com/g/2005#work">(555) 678-1111</gd:phoneNumber>
//         <gContact:groupMembershipInfo deleted="false" href="http://www.google.com/123"/>
//         <gContact:groupMembershipInfo deleted="false" href="http://www.google.com/456"/>
//     </entry>
// </someEntries>
// 

let xml = chilkat::Xml::new();

let _ = xml.load_xml_file("qa_data/xml/georgeCostanza.xml").is_ok();

let num_phone_numbers = xml.num_children_having_tag("entry|*:phoneNumber");
let mut i = 0;
while i < num_phone_numbers {
    let x_phone_number = xml.get_nth_child_with_tag("entry|*:phoneNumber", i).unwrap();
    println!("{}", x_phone_number.content());

    i = i + 1;
}

println!("----");

let num_group_memberships = xml.num_children_having_tag("entry|*:groupMembershipInfo");
i = 0;
while i < num_group_memberships {
    let x_membership = xml.get_nth_child_with_tag("entry|*:groupMembershipInfo", i).unwrap();
    println!("{}", x_membership.get_attr_value("href").unwrap_or_default());

    i = i + 1;
}