(Ruby) Unzip Files Matching a Pattern (such as *.xml)

Example code to unzip Files Matching a Pattern (such as *.xml)

Chilkat Ruby Downloads install from rubygems.org gem install chilkat or download... Ruby Library for Windows, MacOS, Linux, Alpine Linux

require 'chilkat'

# This example works with the .zip located at http://www.example-code.com/data/test.zip

# This example assumes the Chilkat API to have been previously unlocked.
# See Global Unlock Sample for sample code.

# First, let's download the .zip
http = Chilkat::CkHttp.new()
success = http.Download("http://www.example-code.com/data/test.zip","qa_test/test.zip")
if (success != true)
    print http.lastErrorText() + "\n";
    exit
end

zip = Chilkat::CkZip.new()

success = zip.OpenZip("qa_test/test.zip")
if (success != true)
    print zip.lastErrorText() + "\n";
    exit
end

# Show what's in the .zip by getting the directory as XML.
zipContentsXml = zip.getDirectoryAsXML()
if (zip.get_LastMethodSuccess() != true)
    print zip.lastErrorText() + "\n";
    exit
end

print zipContentsXml + "\n";

# In this case, the contents of our .zip look like this:
# <?xml version="1.0" encoding="utf-8" ?>
# <zip_contents>
#     <dir name="test">
#         <dir name="abc">
#             <dir name="123">
#                 <file>ecc_public.pem</file>
#                 <file>starfish.jpg</file>
#             </dir>
#             <file>comodo-certificates.pem</file>
#             <file>pigs.xml</file>
#         </dir>
#         <file>COMODORSACertificationAuthority.crt</file>
#         <file>hamlet.xml</file>
#     </dir>
# </zip_contents>

# ------------------------------------------------------------------------
# If we wish to unzip only .xml files, use "*.xml" for the pattern\
# Unzip to the "qa_output" directory relative to our current working directory.
# (You may unzip to an absolute path by passing an absolute path, such as "/someDir" or
# "C:/someDir", etc.)
# This will unzip only the .xml files.  The relative directory structure within
# the .zip will be created in the local filesystem under the unzip directory
# path passed in the first argument, which in this case is "qa_output".
count = zip.UnzipMatching("qa_output","*.xml",true)
if (count < 0)
    print zip.lastErrorText() + "\n";
    exit
end

print "unzipped " + count.to_s() + " matching file(s)." + "\n";

# ------------------------------------------------------------------------
# If we wish to unzip only files under the "123" directory, we can do this:
count = zip.UnzipMatching("qa_output2","*/123/*",true)
if (count < 0)
    print zip.lastErrorText() + "\n";
    exit
end

print "unzipped " + count.to_s() + " matching file(s)." + "\n";

# ------------------------------------------------------------------------
# If no asterisk character is used, then the match must be exact.
# For example, to unzip "test/hamlet.xml" we must pass the exact path
# as it is in the .zip.  We cannot just pass "hamlet.xml".
count = zip.UnzipMatching("qa_output3","test/hamlet.xml",true)
if (count < 0)
    print zip.lastErrorText() + "\n";
    exit
end

print "unzipped " + count.to_s() + " matching file(s)." + "\n";

# ------------------------------------------------------------------------
# If we want to unzip any file named "hamlet.xml" found in any sub-directory...
count = zip.UnzipMatching("qa_output4","*/hamlet.xml",true)
if (count < 0)
    print zip.lastErrorText() + "\n";
    exit
end

print "unzipped " + count.to_s() + " matching file(s)." + "\n";