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(Ruby) Unzip Files Matching a Pattern (such as *.xml)

Example code to unzip Files Matching a Pattern (such as *.xml)

Chilkat Ruby Downloads

Ruby Library for Linux and MAC OS X

require 'chilkat'

#  This example works with the .zip located at http://www.example-code.com/data/test.zip

#  This example assumes the Chilkat API to have been previously unlocked.
#  See Global Unlock Sample for sample code.

#  First, let's download the .zip
http = Chilkat::CkHttp.new()
success = http.Download("http://www.example-code.com/data/test.zip","qa_test/test.zip")
if (success != true)
    print http.lastErrorText() + "\n";
    exit
end

zip = Chilkat::CkZip.new()

success = zip.OpenZip("qa_test/test.zip")
if (success != true)
    print zip.lastErrorText() + "\n";
    exit
end

#  Show what's in the .zip by getting the directory as XML.
zipContentsXml = zip.getDirectoryAsXML()
if (zip.get_LastMethodSuccess() != true)
    print zip.lastErrorText() + "\n";
    exit
end

print zipContentsXml + "\n";

#  In this case, the contents of our .zip look like this:
#  <?xml version="1.0" encoding="utf-8" ?>
#  <zip_contents>
#      <dir name="test">
#          <dir name="abc">
#              <dir name="123">
#                  <file>ecc_public.pem</file>
#                  <file>starfish.jpg</file>
#              </dir>
#              <file>comodo-certificates.pem</file>
#              <file>pigs.xml</file>
#          </dir>
#          <file>COMODORSACertificationAuthority.crt</file>
#          <file>hamlet.xml</file>
#      </dir>
#  </zip_contents>

#  ------------------------------------------------------------------------
#  If we wish to unzip only .xml files, use "*.xml" for the pattern\
#  Unzip to the "qa_output" directory relative to our current working directory.
#  (You may unzip to an absolute path by passing an absolute path, such as "/someDir" or
#  "C:/someDir", etc.)
#  This will unzip only the .xml files.  The relative directory structure within
#  the .zip will be created in the local filesystem under the unzip directory
#  path passed in the first argument, which in this case is "qa_output".
count = zip.UnzipMatching("qa_output","*.xml",true)
if (count < 0)
    print zip.lastErrorText() + "\n";
    exit
end

print "unzipped " + count.to_s() + " matching file(s)." + "\n";

#  ------------------------------------------------------------------------
#  If we wish to unzip only files under the "123" directory, we can do this:
count = zip.UnzipMatching("qa_output2","*/123/*",true)
if (count < 0)
    print zip.lastErrorText() + "\n";
    exit
end

print "unzipped " + count.to_s() + " matching file(s)." + "\n";

#  ------------------------------------------------------------------------
#  If no asterisk character is used, then the match must be exact.
#  For example, to unzip "test/hamlet.xml" we must pass the exact path
#  as it is in the .zip.  We cannot just pass "hamlet.xml".
count = zip.UnzipMatching("qa_output3","test/hamlet.xml",true)
if (count < 0)
    print zip.lastErrorText() + "\n";
    exit
end

print "unzipped " + count.to_s() + " matching file(s)." + "\n";

#  ------------------------------------------------------------------------
#  If we want to unzip any file named "hamlet.xml" found in any sub-directory...
count = zip.UnzipMatching("qa_output4","*/hamlet.xml",true)
if (count < 0)
    print zip.lastErrorText() + "\n";
    exit
end

print "unzipped " + count.to_s() + " matching file(s)." + "\n";

 

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