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(Ruby) GetChild* methods

Demonstrates several of the GetChild* methods.

The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

The output XML is this:

<abc b="pear" c="orange" a="130">Test</abc>

Chilkat Ruby Downloads

install from rubygems.org

gem install chilkat

or download... Ruby Library for Windows, MacOS, Linux, Alpine Linux

require 'chilkat'

xml = Chilkat::CkXml.new()

# The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
success = xml.LoadXmlFile("get_child.xml")
if (success != true)
    print xml.lastErrorText() + "\n";
    exit
end

# The NumChildren property contains the number of direct
# child nodes.  Note: The child nodes under "xyz" are NOT
# direct children of "root".  Therefore, the "root" node has
# 7 direct children
print "NumChildren = " + xml.get_NumChildren().to_s() + "\n";

# Iterate over the direct children by index. The first child
# is at index 0.

for i in 0 .. xml.get_NumChildren() - 1
    #  access the tag and content directly by index:
    print i.to_s() + ": " + xml.getChildTagByIndex(i) + " : " + xml.getChildContentByIndex(i) + "\n";

end
print "-----" + "\n";

# Do the same as the above loop, but get the child node
# and access the Tag and Content properties:
for i in 0 .. xml.get_NumChildren() - 1
    # child is a CkXml
    child = xml.GetChild(i)
    print i.to_s() + ": " + child.tag() + " : " + child.content() + "\n";

end
print "-----" + "\n";

# Do the same as the above loop, but instead of creating
# a new object instance for each child, call GetChild2 to
# update the object's reference instead.
for i in 0 .. xml.get_NumChildren() - 1
    # Navigate to the Nth child.  
    success = xml.GetChild2(i)
    print i.to_s() + ": " + xml.tag() + " : " + xml.content() + "\n";
    # Navigate back up to the parent:
    success = xml.GetParent2()
end
print "-----" + "\n";

# Examine the result:
print xml.getXml() + "\n";

 

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