Ruby

Parsing XML Children Having Identical Tags

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Demonstrates how to deal with XML where child elements may have identical tags. Ruby

require 'chilkat'

success = false

# This example will get the phoneNumber's and groupMembershihpInfo's from the following XML:

# <?xml version="1.0" encoding="UTF-8" ?>
# <someEntries>
#     <entry>
#         <id>123</id>
#         <updated>2017-07-19T05:19:57.761Z</updated>
#         <app:edited xmlns:app="http://www.w3.org/2007/app">2017-07-19T05:19:57.761Z</app:edited>
#         <category scheme="http://schemas.google.com/g/2005#kind" term="http://schemas.google.com/contact/2008#contact"/>
#         <title>George Costanza</title>
#          <gd:name>
#             <gd:fullName>George Costanza</gd:fullName>
#             <gd:givenName>George</gd:givenName>
#             <gd:familyName>Costanza</gd:familyName>
#         </gd:name>
#         <gd:phoneNumber rel="http://schemas.google.com/g/2005#home">(555) 123-4567</gd:phoneNumber>
#         <gd:phoneNumber rel="http://schemas.google.com/g/2005#mobile">(555) 444-8877</gd:phoneNumber>
#         <gd:phoneNumber rel="http://schemas.google.com/g/2005#work">(555) 678-1111</gd:phoneNumber>
#         <gContact:groupMembershipInfo deleted="false" href="http://www.google.com/123"/>
#         <gContact:groupMembershipInfo deleted="false" href="http://www.google.com/456"/>
#     </entry>
# </someEntries>
# 

xml = Chilkat::CkXml.new()

success = xml.LoadXmlFile("qa_data/xml/georgeCostanza.xml")

numPhoneNumbers = xml.NumChildrenHavingTag("entry|*:phoneNumber")
i = 0
while i < numPhoneNumbers
    # xPhoneNumber is a CkXml
    xPhoneNumber = xml.GetNthChildWithTag("entry|*:phoneNumber",i)
    print xPhoneNumber.content() + "\n";

    i = i + 1
end
print "----" + "\n";

numGroupMemberships = xml.NumChildrenHavingTag("entry|*:groupMembershipInfo")
i = 0
while i < numGroupMemberships
    # xMembership is a CkXml
    xMembership = xml.GetNthChildWithTag("entry|*:groupMembershipInfo",i)
    print xMembership.getAttrValue("href") + "\n";

    i = i + 1
end