Ruby Requires Chilkat v11.0.0+

Duplicate PHP RSA Encryption

See more RSA Examples

Demonstrates how to duplicate the following PHP function. Ruby

require 'chilkat'

success = false

#  This example requires the Chilkat API to have been previously unlocked.
#  See Global Unlock Sample for sample code.

#  Duplicate the following PHP code:
#  
#     public function encryptRSA($plainText,$rsaMOD,$pubKEY){
#          $rsa  = new RSA();
#          $rsa->setEncryptionMode(RSA::ENCRYPTION_PKCS1);
#          $publicKey = [
#              'e' => new BigInteger($pubKEY,16),
#              'n' => new BigInteger($rsaMOD,16)
#          ];
#  		
#          $rsa->loadKey($publicKey);
#          $ciphertext = $rsa->encrypt($plainText);
#          return bin2hex($ciphertext);
#      }
#  
#      $plainText="key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678"
#      $rsaMOD="F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673"
#      $pubKEY="010001"

#  We have the RSA modulus in hex
rsaMOD = "F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673"

#  The RSA exponent in hex is "010001", which is 65537 in decimal.  It's typically the exponent that is always used.
rsaEXP = "010001"

#  Get the RSA modulus and exponent in base64.
bdMod = Chilkat::CkBinData.new()
bdExp = Chilkat::CkBinData.new()
success = bdMod.AppendEncoded(rsaMOD,"hex")
success = bdExp.AppendEncoded(rsaEXP,"hex")

#  Build the XML representation of the RSA public key
xml = Chilkat::CkXml.new()
xml.put_Tag("RSAPublicKey")
xml.UpdateChildContent("Modulus",bdMod.getEncoded("base64"))
xml.UpdateChildContent("Exponent",bdExp.getEncoded("base64"))

#  Load the RSA public key into a Chilkat public key object.
pubkey = Chilkat::CkPublicKey.new()
success = pubkey.LoadFromString(xml.getXml())

#  Setup the RSA object for encryption and do it..
rsa = Chilkat::CkRsa.new()
rsa.put_VerboseLogging(true)
success = rsa.UsePublicKey(pubkey)

#  Use PKCSv1.5 padding
rsa.put_PkcsPadding(true)

#  Encrypt and return the string as hex.
rsa.put_EncodingMode("hex")
plainText = "key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678"
cipherText = rsa.encryptStringENC(plainText,false)
if (rsa.get_LastMethodSuccess() == false)
    print rsa.lastErrorText() + "\n";
    exit
end

#  Note: The PKCSv1_5 padding incorporates random bytes.  Therefore, the RSA encryption will produce different results each time -- all of which are valid 
#  and decrypt correctly to the same original text.
print cipherText + "\n";