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| (Ruby) Duplicate PHP RSA EncryptionDemonstrates how to duplicate the following PHP function. Note: This example requires Chilkat v11.0.0 or greater. 
 require 'chilkat' success = false # This example requires the Chilkat API to have been previously unlocked. # See Global Unlock Sample for sample code. # Duplicate the following PHP code: # # public function encryptRSA($plainText,$rsaMOD,$pubKEY){ # $rsa = new RSA(); # $rsa->setEncryptionMode(RSA::ENCRYPTION_PKCS1); # $publicKey = [ # 'e' => new BigInteger($pubKEY,16), # 'n' => new BigInteger($rsaMOD,16) # ]; # # $rsa->loadKey($publicKey); # $ciphertext = $rsa->encrypt($plainText); # return bin2hex($ciphertext); # } # # $plainText="key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678" # $rsaMOD="F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673" # $pubKEY="010001" # We have the RSA modulus in hex rsaMOD = "F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673" # The RSA exponent in hex is "010001", which is 65537 in decimal. It's typically the exponent that is always used. rsaEXP = "010001" # Get the RSA modulus and exponent in base64. bdMod = Chilkat::CkBinData.new() bdExp = Chilkat::CkBinData.new() success = bdMod.AppendEncoded(rsaMOD,"hex") success = bdExp.AppendEncoded(rsaEXP,"hex") # Build the XML representation of the RSA public key xml = Chilkat::CkXml.new() xml.put_Tag("RSAPublicKey") xml.UpdateChildContent("Modulus",bdMod.getEncoded("base64")) xml.UpdateChildContent("Exponent",bdExp.getEncoded("base64")) # Load the RSA public key into a Chilkat public key object. pubkey = Chilkat::CkPublicKey.new() success = pubkey.LoadFromString(xml.getXml()) # Setup the RSA object for encryption and do it.. rsa = Chilkat::CkRsa.new() rsa.put_VerboseLogging(true) success = rsa.UsePublicKey(pubkey) # Use PKCSv1.5 padding rsa.put_PkcsPadding(true) # Encrypt and return the string as hex. rsa.put_EncodingMode("hex") plainText = "key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678" cipherText = rsa.encryptStringENC(plainText,false) if (rsa.get_LastMethodSuccess() == false) print rsa.lastErrorText() + "\n"; exit end # Note: The PKCSv1_5 padding incorporates random bytes. Therefore, the RSA encryption will produce different results each time -- all of which are valid # and decrypt correctly to the same original text. print cipherText + "\n"; | ||||
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