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(Python) HTTP POST (Duplicate Simple HTML Form POST)Demonstrates how to duplicate a simple HTML form POST.
import sys import chilkat # This example requires the Chilkat API to have been previously unlocked. # See Global Unlock Sample for sample code. req = chilkat.CkHttpRequest() http = chilkat.CkHttp() # This example simulates this FORM: # <form action="echoPost.asp" method="post"> # First name: <input type="text" name="firstName"><br /> # Last name: <input type="text" name="lastName"><br /> # <input type="submit" value="Submit"> # </form> # The online FORM is found at this URL: # https://www.chilkatsoft.com/simpleForm.html # Build an HTTP POST Request: req.put_HttpVerb("POST") # The FORM target is http://www.chilkatsoft.com/processPost.asp # An easy way of filling out most of the HTTP request object # is to call SetFromUrl: req.SetFromUrl("https://www.chilkatsoft.com/echoPost.asp") # Send form params using application/x-www-form-urlencoded req.put_ContentType("application/x-www-form-urlencoded") # The only remaining task is to add the params to the # HTTP request object: req.AddParam("firstName","Matt") req.AddParam("lastName","Jones") # Send the HTTP POST and get the response. # The POST is being sent to chilkatsoft.com, on port 443 (using TLS) domain = "chilkatsoft.com" port = 443 tls = True # The HTTP POST is sent here: # resp is a CkHttpResponse resp = http.SynchronousRequest(domain,port,tls,req) if (http.get_LastMethodSuccess() == False): print(http.lastErrorText()) sys.exit() # Display the HTML source of the page returned. print(resp.bodyStr()) |
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