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(PowerShell) Get the Index of a JSON MemberThis example demonstrates how to get the index of a given member by name. { "name": "donut", "image": { "fname": "donut.jpg", "w": 200, "h": 200 }, "thumbnail": { "fname": "donutThumb.jpg", "w": 32, "h": 32 } }
Add-Type -Path "C:\chilkat\ChilkatDotNet47-9.5.0-x64\ChilkatDotNet47.dll" $json = New-Object Chilkat.JsonObject # This is the above JSON with whitespace chars removed (SPACE, TAB, CR, and LF chars). # The presence of whitespace chars for pretty-printing makes no difference to the Load # method. $jsonStr = "{`"name`": `"donut`",`"image`":{`"fname`": `"donut.jpg`",`"w`": 200,`"h`": 200},`"thumbnail`":{`"fname`": `"donutThumb.jpg`",`"w`": 32,`"h`": 32}}" $success = $json.Load($jsonStr) if ($success -ne $true) { $($json.LastErrorText) exit } # The top-level JSON object has three members: name, image, and thumbnail. $nameIndex = $json.IndexOf("name") # The index of the "name" member is 0. $("nameIndex = " + $nameIndex) $thumbIndex = $json.IndexOf("thumbnail") # The index of the "thumbnail" member is 2. $("thumbIndex = " + $thumbIndex) # The "fname" member is NOT a direct member of the top-level JSON object. # It is a member of a nested object. If we try to get the index of this # member using the top-level JSON object, it is not found (and returns -1). $fnameIndex = $json.IndexOf("fname") # The fnameIndex is -1 (not found). This is correct. $("fnameIndex = " + $fnameIndex) # Get the "image" object. $imageObj = $json.ObjectOf("image") if ($json.LastMethodSuccess -eq $false) { $("image object not found.") exit } # Now we can get the index of the "fname" object, because it is a direct # member of the "image" object: $fnameIndex = $imageObj.IndexOf("fname") $("fnameIndex = " + $fnameIndex) |
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