PowerShell

Duplicate PHP RSA Encryption

See more RSA Examples

Demonstrates how to duplicate the following PHP function. PowerShell

Add-Type -Path "C:\chilkat\ChilkatDotNet47-x64\ChilkatDotNet47.dll"

$success = $false

# This example requires the Chilkat API to have been previously unlocked.
# See Global Unlock Sample for sample code.

# Duplicate the following PHP code:
# 
#    public function encryptRSA($plainText,$rsaMOD,$pubKEY){
#         $rsa  = new RSA();
#         $rsa->setEncryptionMode(RSA::ENCRYPTION_PKCS1);
#         $publicKey = [
#             'e' => new BigInteger($pubKEY,16),
#             'n' => new BigInteger($rsaMOD,16)
#         ];
# 		
#         $rsa->loadKey($publicKey);
#         $ciphertext = $rsa->encrypt($plainText);
#         return bin2hex($ciphertext);
#     }
# 
#     $plainText="key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678"
#     $rsaMOD="F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673"
#     $pubKEY="010001"

# We have the RSA modulus in hex
$rsaMOD = "F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673"

# The RSA exponent in hex is "010001", which is 65537 in decimal.  It's typically the exponent that is always used.
$rsaEXP = "010001"

# Get the RSA modulus and exponent in base64.
$bdMod = New-Object Chilkat.BinData
$bdExp = New-Object Chilkat.BinData
$success = $bdMod.AppendEncoded($rsaMOD,"hex")
$success = $bdExp.AppendEncoded($rsaEXP,"hex")

# Build the XML representation of the RSA public key
$xml = New-Object Chilkat.Xml
$xml.Tag = "RSAPublicKey"
$xml.UpdateChildContent("Modulus",$bdMod.GetEncoded("base64"))
$xml.UpdateChildContent("Exponent",$bdExp.GetEncoded("base64"))

# Load the RSA public key into a Chilkat public key object.
$pubkey = New-Object Chilkat.PublicKey
$success = $pubkey.LoadFromString($xml.GetXml())

# Setup the RSA object for encryption and do it..
$rsa = New-Object Chilkat.Rsa
$rsa.VerboseLogging = $true
$success = $rsa.UsePublicKey($pubkey)

# Use PKCSv1.5 padding
$rsa.PkcsPadding = $true

# Encrypt and return the string as hex.
$rsa.EncodingMode = "hex"
$plainText = "key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678"
$cipherText = $rsa.EncryptStringENC($plainText,$false)
if ($rsa.LastMethodSuccess -eq $false) {
    $($rsa.LastErrorText)
    exit
}

# Note: The PKCSv1_5 padding incorporates random bytes.  Therefore, the RSA encryption will produce different results each time -- all of which are valid 
# and decrypt correctly to the same original text.
$($cipherText)