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(PowerShell) Duplicate PHP RSA EncryptionDemonstrates how to duplicate the following PHP function.
Add-Type -Path "C:\chilkat\ChilkatDotNet47-9.5.0-x64\ChilkatDotNet47.dll" # This example requires the Chilkat API to have been previously unlocked. # See Global Unlock Sample for sample code. # Duplicate the following PHP code: # # public function encryptRSA($plainText,$rsaMOD,$pubKEY){ # $rsa = new RSA(); # $rsa->setEncryptionMode(RSA::ENCRYPTION_PKCS1); # $publicKey = [ # 'e' => new BigInteger($pubKEY,16), # 'n' => new BigInteger($rsaMOD,16) # ]; # # $rsa->loadKey($publicKey); # $ciphertext = $rsa->encrypt($plainText); # return bin2hex($ciphertext); # } # # $plainText="key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678" # $rsaMOD="F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673" # $pubKEY="010001" # We have the RSA modulus in hex $rsaMOD = "F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673" # The RSA exponent in hex is "010001", which is 65537 in decimal. It's typically the exponent that is always used. $rsaEXP = "010001" # Get the RSA modulus and exponent in base64. $bdMod = New-Object Chilkat.BinData $bdExp = New-Object Chilkat.BinData $success = $bdMod.AppendEncoded($rsaMOD,"hex") $success = $bdExp.AppendEncoded($rsaEXP,"hex") # Build the XML representation of the RSA public key $xml = New-Object Chilkat.Xml $xml.Tag = "RSAPublicKey" $xml.UpdateChildContent("Modulus",$bdMod.GetEncoded("base64")) $xml.UpdateChildContent("Exponent",$bdExp.GetEncoded("base64")) # Load the RSA public key into a Chilkat public key object. $pubkey = New-Object Chilkat.PublicKey $success = $pubkey.LoadFromString($xml.GetXml()) # Setup the RSA object for encryption and do it.. $rsa = New-Object Chilkat.Rsa $rsa.VerboseLogging = $true $success = $rsa.ImportPublicKeyObj($pubkey) # Use PKCSv1.5 padding $rsa.OaepPadding = $false # Encrypt and return the string as hex. $rsa.EncodingMode = "hex" $plainText = "key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678" $cipherText = $rsa.EncryptStringENC($plainText,$false) if ($rsa.LastMethodSuccess -eq $false) { $($rsa.LastErrorText) exit } # Note: The PKCSv1_5 padding incorporates random bytes. Therefore, the RSA encryption will produce different results each time -- all of which are valid # and decrypt correctly to the same original text. $($cipherText) |
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