PowerBuilder

Duplicating a Simple HTML Form Submission (POST)

This example shows how to duplicate a simple HTML form submission. The HTML to be duplicated is shown below, and may be tested in a browser by going to this URL: http://www.chilkatsoft.com/postSample.html


<html>
<body>
<form action="echoPost.asp" method="post">
<p>First name: <input name="firstname"></p>
<p>Last name: <input name="lastname"></p>
<p>Your favorite color:
<select name="color">
<option>Blue</option>
<option>Green</option>
<option>Red</option>
<option>Yellow</option>
<option>Pink</option>
</select>
</p>
<input type="hidden" name="myHiddenField1", value="Hidden Value 1">
<input type="hidden" name="myHiddenField2", value="Hidden Value 2">
<p><input type="submit" value="Send POST"></p>
</form>

</body>
</html>

By default, a browser will send a form POST as an HTTP reqeuest using a Content-Type of "application/x-www-form-urlencoded". This is because the form parameters are sent in the body of the HTTP POST using the URL encoding. Therefore, one should use the PostUrlEncoded method to duplicate the form submission.

Each "input" or "select" tag found in the HTML is a form parameter having a name and value. These are duplicated in code by calling AddParam on the HTTP Request object for each parameter.

The target URL is indicated by the "action" attribute on the "form" tag. In the HTML form shown above, it is "echoPost.asp". The URL specified in the "action" attribute may be an absolute or relative URL. In this case, it is a relative URL, and since there is no directory path, the full URL of the POST target is "http://www.chilkatsoft.com/echoPost.asp". This will be the 1st argument passed to the PostUrlEncoded method.

The raw HTTP POST sent to the web server in this example is shown below. The form parameters are located in the body of the request (i.e. under the header fields), and they are URL encoded.

POST /echoPost.asp HTTP/1.1
Content-Type: application/x-www-form-urlencoded
Host: www.chilkatsoft.com
Content-Length: 87

firstname=John&lastname=Doe&myHiddenField1=Hidden+Value+1&myHiddenField2=Hidden+Value+2

Note: An HTTP file upload is a form submission having an "input" tag w/ "type=file". In this case, a browser will send the POST using a content-type of "multipart/form-data". The PostUrlEncoded method should not be called for HTTP file uploads. The SynchronousRequest would instead be called.

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integer li_rc
integer li_Success
oleobject loo_Http
oleobject loo_Req
oleobject loo_Resp

li_Success = 0

// This example requires the Chilkat API to have been previously unlocked.
// See Global Unlock Sample for sample code.

loo_Http = create oleobject
li_rc = loo_Http.ConnectToNewObject("Chilkat.Http")
if li_rc < 0 then
    destroy loo_Http
    MessageBox("Error","Connecting to COM object failed")
    return
end if

loo_Req = create oleobject
li_rc = loo_Req.ConnectToNewObject("Chilkat.HttpRequest")

// Add the form parameters to the HTTP request:
loo_Req.AddParam("firstname","John")
loo_Req.AddParam("lastname","Doe")
loo_Req.AddParam("myHiddenField1","Hidden Value 1")
loo_Req.AddParam("myHiddenField2","Hidden Value 2")

loo_Req.HttpVerb = "POST"
loo_Req.ContentType = "application/x-www-form-urlencoded"

loo_Resp = create oleobject
li_rc = loo_Resp.ConnectToNewObject("Chilkat.HttpResponse")

li_Success = loo_Http.HttpReq("http://www.chilkatsoft.com/echoPost.asp",loo_Req,loo_Resp)
if li_Success = 0 then
    Write-Debug loo_Http.LastErrorText
    destroy loo_Http
    destroy loo_Req
    destroy loo_Resp
    return
end if

// Display the Body of the HTTP resp
// (This is the HTML that the browser would receive if it
// had been an interactive form submission from the browser.)
Write-Debug loo_Resp.BodyStr


destroy loo_Http
destroy loo_Req
destroy loo_Resp