PHP Extension

Async Accept Socket Connection

See more Socket/SSL/TLS Examples

Demonstrates how to get the connected client socket after accepting a connection asynchronously. PHP Extension

<?php

include("chilkat.php");

$success = false;

// This example assumes the Chilkat Socket API to have been previously unlocked.
// See Socket Unlock Sample for sample code.

$listenSocket = new CkSocket();

// Bind to a port and listen.
// This example will listen at port 5555 and allows for a backlog
// of 25 pending connection requests.
$success = $listenSocket->BindAndListen(5555,25);
if ($success != true) {
    print $listenSocket->lastErrorText() . "\n";
    exit;
}

// Start a background task to accept an incoming connection ...
$maxWaitMs = 20000;
// acceptTask is a CkTask
$acceptTask = $listenSocket->AcceptNextConnectionAsync($maxWaitMs);
$acceptTask->Run();

// ...
// ...
// ...

// Imagine at this point the task has completed successfully,
// and a connection was accepted.  Here's how to get the connected socket...
$connectedClient = new CkSocket();
$success = $connectedClient->LoadTaskResult($acceptTask);

// Here's how it works:  The AcceptNextConnection method would normally
// return a socket object when called synchronously.  When called asynchronously,
// it cannot do so because it returns the task object.  When the async method
// (running in a background thread) completes, the socket object that is the client
// connection is contained within the task object.
// 
// This can be generalized for any case where a Chilkat method returns an object.
// The async version of that method is such that the object returned in the background
// thread is contained within the task object.

// To get the result object, we create a new object instance of that type.
// In this case, we create a socket object (connectedClient).  There is a LoadTaskResult
// method in all Chilkat classes that can be a return value of an async method call.
// The LoadTaskResult method transfers the returned object from the task to the caller.

?>