Lazarus Pascal
Lazarus Pascal
Iterate over Direct Child Nodes by Index
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Demonstrates some ways to iterate over direct child nodes by index.The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:
<root>
<fruit color="red">apple</fruit>
<fruit color="green">pear</fruit>
<veg color="orange">carrot</veg>
<meat animal="cow">beef</meat>
<xyz>
<fruit color="blue">blueberry</fruit>
<veg color="green">broccoli</veg>
</xyz>
<fruit color="purple">grape</fruit>
<cheese color="yellow">cheddar</cheese>
</root>
Chilkat Lazarus Pascal Downloads
program ChilkatDemo;
// Demonstrates using the Chilkat Pascal wrapper via the C bridge DLL.
// Builds as a console application under Lazarus (FPC) or Delphi.
{$IFDEF FPC}
{$MODE DELPHI}
{$ENDIF}
{$APPTYPE CONSOLE}
uses
{$IFDEF UNIX}
cthreads,
{$ENDIF}
SysUtils,
CkDllLoader,
Chilkat.Xml;
// ---------------------------------------------------------------------------
procedure RunDemo;
var
success: Boolean;
xml: TXml;
child: TXml;
i: Integer;
begin
success := False;
xml := TXml.Create;
// The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
success := xml.LoadXmlFile('get_child.xml');
if (success <> True) then
begin
WriteLn(xml.LastErrorText);
Exit;
end;
// The NumChildren property contains the number of direct
// child nodes. Note: The child nodes under "xyz" are NOT
// direct children of "root". Therefore, the "root" node has
// 7 direct children
WriteLn('NumChildren = ' + xml.NumChildren);
// Iterate over the direct children by index. The first child
// is at index 0.
for i := 0 to xml.NumChildren - 1 do
begin
// access the tag and content directly by index:
WriteLn(i + ': ' + xml.GetChildTagByIndex(i) + ' : ' + xml.GetChildContentByIndex(i));
end;
WriteLn('-----');
// Do the same as the above loop, but get the child node
// and access the Tag and Content properties:
for i := 0 to xml.NumChildren - 1 do
begin
child := xml.GetChild(i);
WriteLn(i + ': ' + child.Tag + ' : ' + child.Content);
child.Free;
end;
WriteLn('-----');
// Do the same as the above loop, but instead of creating
// a new object instance for each child, call GetChild2 to
// update the object's reference instead.
for i := 0 to xml.NumChildren - 1 do
begin
// Navigate to the Nth child.
success := xml.GetChild2(i);
WriteLn(i + ': ' + xml.Tag + ' : ' + xml.Content);
// Navigate back up to the parent:
success := xml.GetParent2();
end;
WriteLn('-----');
// Notice that the Content of the "xyz" node is empty. This is correct.
// The "xyz" node has no Content, but 2 direct children.
xml.Free;
end;
// ---------------------------------------------------------------------------
begin
try
RunDemo;
except
on E: Exception do
WriteLn('Unhandled exception: ', E.ClassName, ': ', E.Message);
end;
WriteLn;
{$IFDEF MSWINDOWS}
WriteLn('Press Enter to exit...');
ReadLn;
{$ENDIF}
end.