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(Lianja) Duplicate PHP RSA EncryptionDemonstrates how to duplicate the following PHP function.
// This example requires the Chilkat API to have been previously unlocked. // See Global Unlock Sample for sample code. // Duplicate the following PHP code: // // public function encryptRSA($plainText,$rsaMOD,$pubKEY){ // $rsa = new RSA(); // $rsa->setEncryptionMode(RSA::ENCRYPTION_PKCS1); // $publicKey = [ // 'e' => new BigInteger($pubKEY,16), // 'n' => new BigInteger($rsaMOD,16) // ]; // // $rsa->loadKey($publicKey); // $ciphertext = $rsa->encrypt($plainText); // return bin2hex($ciphertext); // } // // $plainText="key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678" // $rsaMOD="F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673" // $pubKEY="010001" // We have the RSA modulus in hex lcRsaMOD = "F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673" // The RSA exponent in hex is "010001", which is 65537 in decimal. It's typically the exponent that is always used. lcRsaEXP = "010001" // Get the RSA modulus and exponent in base64. loBdMod = createobject("CkBinData") loBdExp = createobject("CkBinData") llSuccess = loBdMod.AppendEncoded(lcRsaMOD,"hex") llSuccess = loBdExp.AppendEncoded(lcRsaEXP,"hex") // Build the XML representation of the RSA public key loXml = createobject("CkXml") loXml.Tag = "RSAPublicKey" loXml.UpdateChildContent("Modulus",loBdMod.GetEncoded("base64")) loXml.UpdateChildContent("Exponent",loBdExp.GetEncoded("base64")) // Load the RSA public key into a Chilkat public key object. loPubkey = createobject("CkPublicKey") llSuccess = loPubkey.LoadFromString(loXml.GetXml()) // Setup the RSA object for encryption and do it.. loRsa = createobject("CkRsa") loRsa.VerboseLogging = .T. llSuccess = loRsa.ImportPublicKeyObj(loPubkey) // Use PKCSv1.5 padding loRsa.OaepPadding = .F. // Encrypt and return the string as hex. loRsa.EncodingMode = "hex" lcPlainText = "key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678" lcCipherText = loRsa.EncryptStringENC(lcPlainText,.F.) if (loRsa.LastMethodSuccess = .F.) then ? loRsa.LastErrorText release loBdMod release loBdExp release loXml release loPubkey release loRsa return endif // Note: The PKCSv1_5 padding incorporates random bytes. Therefore, the RSA encryption will produce different results each time -- all of which are valid // and decrypt correctly to the same original text. ? lcCipherText release loBdMod release loBdExp release loXml release loPubkey release loRsa |
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