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(Lianja) Viewing the Raw HTTP Request Generated from a curl CommandSee more CURL ExamplesThis example demonstrates how to convert a By calling In this example, a This technique is helpful when troubleshooting issues related to request composition, encoding, or server-side behavior. Note: This example requires Chilkat v11.5.0 or greater.
llSuccess = .F. // Build a curl command and convert it to the raw HTTP request that would be sent. // This allows you to inspect the exact request (headers + body) without actually sending it. // curl -X POST https://httpbin.org/post \ // -H "Content-Type: application/json" \ // -d '{ // "title": "foo", // "body": "bar", // "userId": 1 // }' // The backslashes at the end of lines are not required. Chilkat ignores them if present. loSbTargetCurl = createobject("CkStringBuilder") loSbTargetCurl.AppendLn(' curl -X POST https://httpbin.org/post \") loSbTargetCurl.AppendLn(' -H "Content-Type: application/json" \") loSbTargetCurl.AppendLn(" -d '{") loSbTargetCurl.AppendLn(' "title": "foo",') loSbTargetCurl.AppendLn(' "body": "bar",') loSbTargetCurl.AppendLn(' "userId": 1') loSbTargetCurl.AppendLn(" }'") loHttpCurl = createobject("CkHttpCurl") // Convert the curl command into a raw HTTP request string. // This is useful for debugging, as it shows exactly what would be sent to the server // (request line, headers, and body) for the given curl command. loSbRawRequest = createobject("CkStringBuilder") llSuccess = loHttpCurl.ToRawRequest(loSbTargetCurl.GetAsString(),loSbRawRequest) if (llSuccess = .F.) then ? loHttpCurl.LastErrorText release loSbTargetCurl release loHttpCurl release loSbRawRequest return endif // Display the generated raw HTTP request. ? loSbRawRequest.GetAsString() // Expected output: // POST /post HTTP/1.1 // Host: httpbin.org // Content-Type: application/json // Content-Length: 96 // // { // "title": "foo", // "body": "bar", // "userId": 1 // } release loSbTargetCurl release loHttpCurl release loSbRawRequest |
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