JavaScript
JavaScript
Unzip Some Files by Iterating over Entries
See more Zip Examples
Demonstrates how to unzip specific files by iterating over entries in a .zip.
Note
This example is intended for running within a Chilkat.Js embedded JavaScript engine. All Chilkat JavaScript examples require Chilkat
v11.4.0 or greater.
var success = false;
// This requires the Chilkat API to have been previously unlocked.
// See Global Unlock Sample for sample code.
var zip = new CkZip();
// Open a .zip containing:
//
// a1.xml
// b1.xml
// c1.xml
// dir1/a2.xml
// dir1/c2.xml
// dir2/dir3/c3.xml
// We wish to unzip only a1.xml, b1.xml, and c1.xml
success = zip.OpenZip("qa_data/zips/xml_files.zip");
if (success == false) {
console.log(zip.LastErrorText);
return;
}
var sbFilename = new CkStringBuilder();
var entry = new CkZipEntry();
var numEntries = zip.NumEntries;
var i = 0;
while (i < numEntries) {
zip.EntryAt(i,entry);
var entryFilePath = entry.FileName;
console.log(entryFilePath);
if (entry.IsDirectory == false) {
sbFilename.SetString(entryFilePath);
if (sbFilename.Contains("/",false) == false) {
// Does not contain "/"
// Unzip to the qa_output directory.
success = entry.Extract("qa_output");
if (success == false) {
console.log("Failed to unzip " + entryFilePath);
}
else {
console.log("Unzipped " + entryFilePath);
}
}
}
i = i+1;
}