Java

Iterate over Direct Children with a Specific Tag

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Demonstrates how to iterate over direct children having a specific tag.

The input XML, available at http://www.chilkatsoft.com/data/fruit.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Java

import com.chilkatsoft.*;

public class ChilkatExample {

  static {
    try {
        System.loadLibrary("chilkat");
    } catch (UnsatisfiedLinkError e) {
      System.err.println("Native code library failed to load.\n" + e);
      System.exit(1);
    }
  }

  public static void main(String argv[])
  {
    boolean success = false;

    CkXml xml = new CkXml();
    CkXml child;
    int numWithTag;
    int i;

    // The sample input XML is available at http://www.chilkatsoft.com/data/fruit.xml
    success = xml.LoadXmlFile("fruit.xml");
    if (success != true) {
        System.out.println(xml.lastErrorText());
        return;
        }

    //  Get the number of direct children having the tag "fruit"
    numWithTag = xml.NumChildrenHavingTag("fruit");

    if (numWithTag > 0) {

        for (i = 0; i <= numWithTag - 1; i++) {
            child = xml.GetNthChildWithTag("fruit",i);
            System.out.println(i + ": " + child.tag() + " : " + child.content());

            }

        System.out.println("-----");

        // Do the same as the above loop, but instead of creating
        // a new object instance for each child, call GetNthChildWithTag2 to
        // update the object's reference instead.
        for (i = 0; i <= numWithTag - 1; i++) {
            // Navigate to the Nth child.  
            success = xml.GetNthChildWithTag2("fruit",i);
            System.out.println(i + ": " + xml.tag() + " : " + xml.content());
            // Navigate back up to the parent:
            success = xml.GetParent2();
            }

        System.out.println("-----");
        }
  }
}