Java

Resolve Domain to IP Address

See more DNS Examples

Demonstrates how to perform a DNS query to obtain A records for resolving a domain name to an IPv4 address. Java

import com.chilkatsoft.*;

public class ChilkatExample {

  static {
    try {
        System.loadLibrary("chilkat");
    } catch (UnsatisfiedLinkError e) {
      System.err.println("Native code library failed to load.\n" + e);
      System.exit(1);
    }
  }

  public static void main(String argv[])
  {
    boolean success = false;

    CkDns dns = new CkDns();

    CkJsonObject json = new CkJsonObject();
    json.put_EmitCompact(false);

    success = dns.Query("A","microsoft.com",json);
    if (success == false) {
        System.out.println(dns.lastErrorText());
        return;
        }

    System.out.println(json.emit());

    //  Sample response.
    //  Parsing code below..

    //  {
    //    "answer": {
    //      "a": [
    //        {
    //          "name": "microsoft.com",
    //          "ttl": 1528,
    //          "ipv4": "20.112.250.133"
    //        },
    //        {
    //          "name": "microsoft.com",
    //          "ttl": 1528,
    //          "ipv4": "20.231.239.246"
    //        },
    //        {
    //          "name": "microsoft.com",
    //          "ttl": 1528,
    //          "ipv4": "20.76.201.171"
    //        },
    //        {
    //          "name": "microsoft.com",
    //          "ttl": 1528,
    //          "ipv4": "20.70.246.20"
    //        },
    //        {
    //          "name": "microsoft.com",
    //          "ttl": 1528,
    //          "ipv4": "20.236.44.162"
    //        }
    //      ]
    //    }
    //  }

    //  Use this online tool to generate parsing code from sample JSON: 
    //  Generate Parsing Code from JSON

    String name;
    int ttl;
    String ipv4;

    int i = 0;
    int count_i = json.SizeOfArray("answer.a");
    while (i < count_i) {
        json.put_I(i);
        name = json.stringOf("answer.a[i].name");
        ttl = json.IntOf("answer.a[i].ttl");
        ipv4 = json.stringOf("answer.a[i].ipv4");
        i = i+1;
        }
  }
}