(Java) Parse Multipart Binary Http Response

This example demonstrates how to parse an HTTP response that is multipart and contains a binary file, such as a .zip or .pdf.

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import com.chilkatsoft.*;

public class ChilkatExample {

  static {
    try {
        System.loadLibrary("chilkat");
    } catch (UnsatisfiedLinkError e) {
      System.err.println("Native code library failed to load.\n" + e);
      System.exit(1);
    }
  }

  public static void main(String argv[])
  {
    // This example requires the Chilkat API to have been previously unlocked.
    // See Global Unlock Sample for sample code.

    boolean success;
    CkHttp http = new CkHttp();

    CkHttpRequest req = new CkHttpRequest();

    // ...
    // Insert code here to construct some kind of HTTP request.
    // this example is to show how to parse a particular kind of response.
    // ...
    // ...

    // Send the request (whatever it may be in your case) to get the HTTP response object.
    CkHttpResponse resp = http.SynchronousRequest("www.somedomain.com",443,true,req);
    if (http.get_LastMethodSuccess() != true) {
        System.out.println(http.lastErrorText());
        return;
        }

    // Get the response body (which is expected to be binary)
    CkBinData respBody = new CkBinData();
    resp.GetBodyBd(respBody);

    // For this example, the response body contains something like this:

    // ------=_Part_21302_2029949381.1547401515443
    // Content-Type: application/xop+xml; charset=UTF-8; type="text/xml"
    // Content-Transfer-Encoding: 8bit
    // Content-ID: <rootpart@ws.jboss.org>
    // 
    // <env:Envelope xmlns:env='http://schemas.xmlsoap.org/soap/envelope/'><env:Header></env:Header><env:Body>...</env:Body></env:Envelope>
    // ------=_Part_21302_2029949381.1547401515443
    // Content-Type: application/octet-stream
    // Content-Transfer-Encoding: binary
    // Content-Id: <fileArchivio-7d302908-4d64-43d3-bf4e-79ce806d43b3@ws.jboss.org>
    // 
    // BINARY_CONTENT_HERE...
    // 
    // ------=_Part_21302_2029949381.1547401515443--
    // 

    // Load it into a Chilkat MIME object.
    CkMime mime = new CkMime();
    success = mime.LoadMimeBd(respBody);
    if (success != true) {
        System.out.println(mime.lastErrorText());
        return;
        }

    int numParts = mime.get_NumParts();
    if (numParts < 2) {
        System.out.println("Expected multipart MIME with at least 2 sub-parts.");
        return;
        }

    // Get the 1st sub-part, which is the XML.
    CkMime part0 = mime.GetPart(0);
    // Should be OK because we checked NumParts above..
    String xmlStr = part0.getBodyDecoded();
    System.out.println(xmlStr);
    System.out.println("----");

    // Save the 2nd part to a file.  (It is a .zip file in our test case..)
    CkMime part1 = mime.GetPart(1);
    success = part1.SaveBody("qa_output/attachedZip.zip");

    // Alternatively, we could extract the binary data to a BinData and use elsewhere..
    CkBinData zipData = new CkBinData();
    success = part1.GetBodyBd(zipData);
    success = zipData.WriteFile("qa_output/attachedZip_again.zip");

    System.out.println("OK.");
  }
}