Go

Iterate over Direct Children with a Specific Tag

See more XML Examples

Demonstrates how to iterate over direct children having a specific tag.

The input XML, available at http://www.chilkatsoft.com/data/fruit.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Go

    success := false

    xml := chilkat.NewXml()
    // child is a Xml
    var numWithTag int
    var i int

    // The sample input XML is available at http://www.chilkatsoft.com/data/fruit.xml
    success = xml.LoadXmlFile("fruit.xml")
    if success != true {
        fmt.Println(xml.LastErrorText())
        xml.DisposeXml()
        return
    }

    //  Get the number of direct children having the tag "fruit"
    numWithTag = xml.NumChildrenHavingTag("fruit")

    if numWithTag > 0 {

        for i = 0; i <= numWithTag - 1; i++ {
            child := xml.GetNthChildWithTag("fruit",i)
            fmt.Println(i, ": ", child.Tag(), " : ", child.Content())
            child.DisposeXml()
        }

        fmt.Println("-----")

        // Do the same as the above loop, but instead of creating
        // a new object instance for each child, call GetNthChildWithTag2 to
        // update the object's reference instead.
        for i = 0; i <= numWithTag - 1; i++ {
            // Navigate to the Nth child.  
            success = xml.GetNthChildWithTag2("fruit",i)
            fmt.Println(i, ": ", xml.Tag(), " : ", xml.Content())
            // Navigate back up to the parent:
            success = xml.GetParent2()
        }

        fmt.Println("-----")
    }


    xml.DisposeXml()