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(Go) HTTP POST and Stream Response to FileDemonstrates how to send an HTTP POST and stream the response body directly to a file.
// This example requires the Chilkat API to have been previously unlocked. // See Global Unlock Sample for sample code. rest := chilkat.NewRest() url := chilkat.NewUrl() // This URL will emit a response that echos the query params (name and age) url.ParseUrl("https://www.chilkatsoft.com/readPost.asp") // Connect to the web server bAutoReconnect := true success := rest.Connect(url.Host(),url.Port(),url.Ssl(),bAutoReconnect) if success != true { fmt.Println(rest.LastErrorText()) rest.DisposeRest() url.DisposeUrl() return } rest.AddQueryParam("name","John") rest.AddQueryParam("age","33") // Send the HTTP POST. success = rest.SendReqFormUrlEncoded("POST",url.Path()) if success != true { fmt.Println(rest.LastErrorText()) rest.DisposeRest() url.DisposeUrl() return } // Read the response header. responseStatusCode := rest.ReadResponseHeader() if responseStatusCode < 0 { fmt.Println(rest.LastErrorText()) rest.DisposeRest() url.DisposeUrl() return } fmt.Println("Response status code = ", responseStatusCode) // We expect a 200 response status if the file data is coming. // Otherwise, we'll get a string response body with an error message(or no response body). if responseStatusCode == 200 { bodyStream := chilkat.NewStream() // The stream's sink will be a file. bodyStream.SetSinkFile("qa_output/out.txt") // Read the response body to the stream. Given that we've // set the stream's sink to a file, it will stream directly // to the file. success = rest.ReadRespBodyStream(bodyStream,true) if success != true { fmt.Println(rest.LastErrorText()) rest.DisposeRest() url.DisposeUrl() bodyStream.DisposeStream() return } fmt.Println("Successfully streamed the response to a file.") } else { errResponse := rest.ReadRespBodyString() if rest.LastMethodSuccess() != true { fmt.Println(rest.LastErrorText()) } else { fmt.Println(*errResponse) } } rest.DisposeRest() url.DisposeUrl() bodyStream.DisposeStream() |
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