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Duplicate PHP RSA Encryption
See more RSA Examples
Demonstrates how to duplicate the following PHP function.Chilkat Go Downloads
success := false
// This example requires the Chilkat API to have been previously unlocked.
// See Global Unlock Sample for sample code.
// Duplicate the following PHP code:
//
// public function encryptRSA($plainText,$rsaMOD,$pubKEY){
// $rsa = new RSA();
// $rsa->setEncryptionMode(RSA::ENCRYPTION_PKCS1);
// $publicKey = [
// 'e' => new BigInteger($pubKEY,16),
// 'n' => new BigInteger($rsaMOD,16)
// ];
//
// $rsa->loadKey($publicKey);
// $ciphertext = $rsa->encrypt($plainText);
// return bin2hex($ciphertext);
// }
//
// $plainText="key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678"
// $rsaMOD="F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673"
// $pubKEY="010001"
// We have the RSA modulus in hex
rsaMOD := "F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673"
// The RSA exponent in hex is "010001", which is 65537 in decimal. It's typically the exponent that is always used.
rsaEXP := "010001"
// Get the RSA modulus and exponent in base64.
bdMod := chilkat.NewBinData()
bdExp := chilkat.NewBinData()
success = bdMod.AppendEncoded(rsaMOD,"hex")
success = bdExp.AppendEncoded(rsaEXP,"hex")
// Build the XML representation of the RSA public key
xml := chilkat.NewXml()
xml.SetTag("RSAPublicKey")
xml.UpdateChildContent("Modulus",*bdMod.GetEncoded("base64"))
xml.UpdateChildContent("Exponent",*bdExp.GetEncoded("base64"))
// Load the RSA public key into a Chilkat public key object.
pubkey := chilkat.NewPublicKey()
success = pubkey.LoadFromString(*xml.GetXml())
// Setup the RSA object for encryption and do it..
rsa := chilkat.NewRsa()
rsa.SetVerboseLogging(true)
success = rsa.UsePublicKey(pubkey)
// Use PKCSv1.5 padding
rsa.SetPkcsPadding(true)
// Encrypt and return the string as hex.
rsa.SetEncodingMode("hex")
plainText := "key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678"
cipherText := rsa.EncryptStringENC(plainText,false)
if rsa.LastMethodSuccess() == false {
fmt.Println(rsa.LastErrorText())
bdMod.DisposeBinData()
bdExp.DisposeBinData()
xml.DisposeXml()
pubkey.DisposePublicKey()
rsa.DisposeRsa()
return
}
// Note: The PKCSv1_5 padding incorporates random bytes. Therefore, the RSA encryption will produce different results each time -- all of which are valid
// and decrypt correctly to the same original text.
fmt.Println(*cipherText)
bdMod.DisposeBinData()
bdExp.DisposeBinData()
xml.DisposeXml()
pubkey.DisposePublicKey()
rsa.DisposeRsa()