Visual FoxPro

Unzip Files Matching a Pattern (such as *.xml)

See more Zip Examples

Example code to unzip Files Matching a Pattern (such as *.xml) Visual FoxPro

LOCAL lnSuccess
LOCAL loHttp
LOCAL loZip
LOCAL lcZipContentsXml
LOCAL lnCount

lnSuccess = 0

* This example works with the .zip located at http://www.example-code.com/data/test.zip

* This example assumes the Chilkat API to have been previously unlocked.
* See Global Unlock Sample for sample code.

* First, let's download the .zip
loHttp = CreateObject('Chilkat.Http')
lnSuccess = loHttp.Download("http://www.example-code.com/data/test.zip","qa_test/test.zip")
IF (lnSuccess <> 1) THEN
    ? loHttp.LastErrorText
    RELEASE loHttp
    CANCEL
ENDIF

loZip = CreateObject('Chilkat.Zip')

lnSuccess = loZip.OpenZip("qa_test/test.zip")
IF (lnSuccess <> 1) THEN
    ? loZip.LastErrorText
    RELEASE loHttp
    RELEASE loZip
    CANCEL
ENDIF

* Show what's in the .zip by getting the directory as XML.
lcZipContentsXml = loZip.GetDirectoryAsXML()
IF (loZip.LastMethodSuccess <> 1) THEN
    ? loZip.LastErrorText
    RELEASE loHttp
    RELEASE loZip
    CANCEL
ENDIF

? lcZipContentsXml

* In this case, the contents of our .zip look like this:
* <?xml version="1.0" encoding="utf-8" ?>
* <zip_contents>
*     <dir name="test">
*         <dir name="abc">
*             <dir name="123">
*                 <file>ecc_public.pem</file>
*                 <file>starfish.jpg</file>
*             </dir>
*             <file>comodo-certificates.pem</file>
*             <file>pigs.xml</file>
*         </dir>
*         <file>COMODORSACertificationAuthority.crt</file>
*         <file>hamlet.xml</file>
*     </dir>
* </zip_contents>

* ------------------------------------------------------------------------
* If we wish to unzip only .xml files, use "*.xml" for the pattern\
* Unzip to the "qa_output" directory relative to our current working directory.
* (You may unzip to an absolute path by passing an absolute path, such as "/someDir" or
* "C:/someDir", etc.)
* This will unzip only the .xml files.  The relative directory structure within
* the .zip will be created in the local filesystem under the unzip directory
* path passed in the first argument, which in this case is "qa_output".
lnCount = loZip.UnzipMatching("qa_output","*.xml",1)
IF (lnCount < 0) THEN
    ? loZip.LastErrorText
    RELEASE loHttp
    RELEASE loZip
    CANCEL
ENDIF

? "unzipped " + STR(lnCount) + " matching file(s)."

* ------------------------------------------------------------------------
* If we wish to unzip only files under the "123" directory, we can do this:
lnCount = loZip.UnzipMatching("qa_output2","*/123/*",1)
IF (lnCount < 0) THEN
    ? loZip.LastErrorText
    RELEASE loHttp
    RELEASE loZip
    CANCEL
ENDIF

? "unzipped " + STR(lnCount) + " matching file(s)."

* ------------------------------------------------------------------------
* If no asterisk character is used, then the match must be exact.
* For example, to unzip "test/hamlet.xml" we must pass the exact path
* as it is in the .zip.  We cannot just pass "hamlet.xml".
lnCount = loZip.UnzipMatching("qa_output3","test/hamlet.xml",1)
IF (lnCount < 0) THEN
    ? loZip.LastErrorText
    RELEASE loHttp
    RELEASE loZip
    CANCEL
ENDIF

? "unzipped " + STR(lnCount) + " matching file(s)."

* ------------------------------------------------------------------------
* If we want to unzip any file named "hamlet.xml" found in any sub-directory...
lnCount = loZip.UnzipMatching("qa_output4","*/hamlet.xml",1)
IF (lnCount < 0) THEN
    ? loZip.LastErrorText
    RELEASE loHttp
    RELEASE loZip
    CANCEL
ENDIF

? "unzipped " + STR(lnCount) + " matching file(s)."

RELEASE loHttp
RELEASE loZip