Visual FoxPro

Simple SOAP Request

See more HTTP Examples

Demonstrates how to send a simple SOAP request. Visual FoxPro

LOCAL lnSuccess
LOCAL loXml
LOCAL lcSoapRequestBody
LOCAL lcEndpoint
LOCAL lcSoapAction
LOCAL lcContentType
LOCAL loHttp
LOCAL loResp
LOCAL loResponseXml
LOCAL lnStatusCode
LOCAL lcDat_NumberToDollarsResult

lnSuccess = 0

* --------------------------------------------------------------------------------
* Also see Chilkat's Online WSDL Code Generator
* to generate code and SOAP Request and Response XML for each operation in a WSDL.
* --------------------------------------------------------------------------------

* Create the following XML to be sent in the SOAP request body.

* <soapenv:Envelope xmlns:dat="http://www.dataaccess.com/webservicesserver/" xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
*     <soapenv:Header/>
*     <soapenv:Body>
*         <dat:NumberToDollars>
*             <dat:dNum>99.0</dat:dNum>
*         </dat:NumberToDollars>
*     </soapenv:Body>
* </soapenv:Envelope>

loXml = CreateObject('Chilkat.Xml')
loXml.Tag = "soapenv:Envelope"
loXml.AddAttribute("xmlns:dat","http://www.dataaccess.com/webservicesserver/")
loXml.AddAttribute("xmlns:soapenv","http://schemas.xmlsoap.org/soap/envelope/")
loXml.UpdateChildContent("soapenv:Header","")
loXml.UpdateChildContent("soapenv:Body|dat:NumberToDollars|dat:dNum","99.0")

* In a SOAP HTTP request, including the XML declaration (<?xml version="1.0" encoding="UTF-8"?>) in the XML body is generally not required. 
loXml.EmitXmlDecl = 0
lcSoapRequestBody = loXml.GetXml()

lcEndpoint = "https://www.dataaccess.com/webservicesserver/numberconversion.wso"
lcSoapAction = ""
*  For SOAP requests, the standard Content-Type is usually set to "text/xml" or "application/soap+xml"
lcContentType = "text/xml"

loHttp = CreateObject('Chilkat.Http')

loHttp.ClearHeaders()
loHttp.SetRequestHeader("SOAPAction",lcSoapAction)

loResp = CreateObject('Chilkat.HttpResponse')
lnSuccess = loHttp.HttpStr("POST",lcEndpoint,lcSoapRequestBody,"utf-8",lcContentType,loResp)
IF (lnSuccess = 0) THEN
    ? loHttp.LastErrorText
    RELEASE loXml
    RELEASE loHttp
    RELEASE loResp
    CANCEL
ENDIF

* Get the XML response body.
loResponseXml = CreateObject('Chilkat.Xml')
loResp.GetBodyXml(loResponseXml)

lnStatusCode = loResp.StatusCode
? "response status code: " + STR(lnStatusCode)

* If the status code does not indicate succcess, then show the response XML,
* which probably contains error information.
IF (lnStatusCode <> 200) THEN
    ? loResponseXml.GetXml()
    RELEASE loXml
    RELEASE loHttp
    RELEASE loResp
    RELEASE loResponseXml
    CANCEL
ENDIF

? loResponseXml.GetXml()

* Parse the successful SOAP response XML.

* This is a sample of the response XML, but the namespace prefixes will be different.
* We can parse the result using "*" for the namespace prefixes (see below).

* <soapenv:Envelope xmlns:dat="http://www.dataaccess.com/webservicesserver/" xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
*     <soapenv:Header/>
*     <soapenv:Body>
*         <dat:NumberToDollarsResponse>
*             <dat:NumberToDollarsResult>string</dat:NumberToDollarsResult>
*         </dat:NumberToDollarsResponse>
*     </soapenv:Body>
* </soapenv:Envelope>

lcDat_NumberToDollarsResult = loResponseXml.GetChildContent("*:Body|*:NumberToDollarsResponse|*:NumberToDollarsResult")
? "result: " + lcDat_NumberToDollarsResult

RELEASE loXml
RELEASE loHttp
RELEASE loResp
RELEASE loResponseXml