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(Visual FoxPro) Demonstrates how to Handle Large Integers in JSONSee more JSON ExamplesDemonstrates how to handle large integers in JSON. (Integers larger than what can fit in a 32-bit signed integer.)
LOCAL loJson LOCAL lnSuccess LOCAL lnId LOCAL lcAccountId * Let's say your JSON has this: * { * "id": 20000000001234567 * } * For versions of Chilkat < 10.0.0, use CreateObject('Chilkat_9_5_0.JsonObject') loJson = CreateObject('Chilkat.JsonObject') lnSuccess = loJson.LoadFile("qa_data/json/large_int.json") IF (lnSuccess = 0) THEN ? loJson.LastErrorText RELEASE loJson CANCEL ENDIF * The integer is too large for a 32-bit signed integer that is returned by IntOf. * The result will be something that wrapped around and could be negative. * In this case it would be: -543893881 lnId = loJson.IntOf("id") ? "id: " + STR(lnId) * The solution is to read the integer value as a string, and then use the features in your programming language * to convert from a string to a 64-bit integer. * * Alternatively, you may wish to simply hold the value as a string. If, for example, the integer simply references * an order ID, an account ID, etc., then there's no need to convert to an integer value. You're not going to be doing * mathematical operations on it anyway. This is usually the case for large integers -- they typically exist * in JSON as an account ID. * You can get any JSON value as a string: lcAccountId = loJson.StringOf("id") ? "accountId: " + lcAccountId * Sample output: * id: -543893881 * accountId: 20000000001234567 RELEASE loJson |
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