Visual FoxPro
Visual FoxPro
Send XMLHttpRequest using PUT, GET, DELETE, or any HTTP Request Method
See more HTTP Examples
The PostXml method is the easiest way to send an XMLHttpRequest using the POST HTTP verb (which is by far the most common). To use a different HTTP request method (such as PUT, GET, DELETE, etc.), the SynchronousRequest method should be called. It provides more flexibility in constructing the exact HTTP request desired.Chilkat Visual FoxPro Downloads
LOCAL lnSuccess
LOCAL loHttp
LOCAL lcXmlStr
LOCAL lcEndpointDomain
LOCAL lnEndpointPort
LOCAL lnEndpointSsl
LOCAL loReq
LOCAL loResp
lnSuccess = 0
* This example assumes the Chilkat API to have been previously unlocked.
* See Global Unlock Sample for sample code.
loHttp = CreateObject('Chilkat.Http')
* The XML sent in the body of the request is application
* specified -- it should contain whatever the server-side
* application is expecting..
lcXmlStr = '<?xml version="1.0" encoding="UTF-8"?><appXml><something>123</something></appXml>'
* If the service endpoint is "http://www.chilkatsoft.com/xmlEcho.asp",
* then we have the following arguments to be passed to
* HttpSReq:
lcEndpointDomain = "www.chilkatsoft.com"
lnEndpointPort = 443
lnEndpointSsl = 1
* Prepare the HTTP request object:
loReq = CreateObject('Chilkat.HttpRequest')
loReq.Path = "/xmlEcho.asp"
* This example will use the "PUT" HTTP request method
* (also known as HTTP verb)
loReq.HttpVerb = "PUT"
loReq.ContentType = "text/xml"
loReq.Charset = "utf-8"
lnSuccess = loReq.LoadBodyFromString(lcXmlStr,"utf-8")
loResp = CreateObject('Chilkat.HttpResponse')
lnSuccess = loHttp.HttpSReq(lcEndpointDomain,lnEndpointPort,lnEndpointSsl,loReq,loResp)
IF (lnSuccess = 0) THEN
? loHttp.LastErrorText
RELEASE loHttp
RELEASE loReq
RELEASE loResp
CANCEL
ENDIF
* The raw HTTP request sent by the above call is:
* PUT /xmlEcho.asp HTTP/1.1
* Content-Type: text/xml
* Host: www.chilkatsoft.com
* Content-Length: 81
*
* <?xml version="1.0" encoding="UTF-8"?><appXml><something>123</something></appXml>
* Examine the Body of the HTTP response
* This would be the XML response sent by the server.
? loResp.BodyStr
RELEASE loHttp
RELEASE loReq
RELEASE loResp