Visual FoxPro
Visual FoxPro
WebDAV PROPFIND
See more HTTP Examples
Demonstrates how to send a WebDAV PROPFIND HTTP request.Chilkat Visual FoxPro Downloads
LOCAL lnSuccess
LOCAL loReq
LOCAL loHttp
LOCAL lcXmlBody
LOCAL loResp
LOCAL lcResponseXml
LOCAL lnStatusCode
lnSuccess = 0
* This example assumes the Chilkat API to have been previously unlocked.
* See Global Unlock Sample for sample code.
loReq = CreateObject('Chilkat.HttpRequest')
loHttp = CreateObject('Chilkat.Http')
* The PROPFIND request to be sent will look similar to this:
* This is from RFC 4918 at http://tools.ietf.org/html/rfc4918#section-9.1.3
* PROPFIND /file HTTP/1.1
* Host: www.example.com
* Content-type: application/xml; charset="utf-8"
* Content-Length: xxxx
*
* <?xml version="1.0" encoding="utf-8" ?>
* <D:propfind xmlns:D="DAV:">
* <D:prop xmlns:R="http://ns.example.com/boxschema/">
* <R:bigbox/>
* <R:author/>
* <R:DingALing/>
* <R:Random/>
* </D:prop>
* </D:propfind>
* Build the HTTP request object.
* The HTTP verb should be "PROPFIND"
loReq.HttpVerb = "PROPFIND"
* The Content-Type should be "application/xml", and
* the charset attribute in the Content-Type header should
* be utf-8:
loReq.ContentType = "application/xml"
loReq.Charset = "utf-8"
loReq.SendCharset = 1
* Load the request body with the XML. Your application
* is free to construct the XML using any means desired.
* Once the XML is prepared, load it into the request body
* like this:
lcXmlBody = "This is the string that should contain the XML body..."
lnSuccess = loReq.LoadBodyFromString(lcXmlBody,"utf-8")
IF (lnSuccess = 0) THEN
? loReq.LastErrorText
RELEASE loReq
RELEASE loHttp
CANCEL
ENDIF
* For this example, pretend the WEBDAV endpoint is:
* https://webdav.chilkatstorage.com/
* Note: There is no actual "chilkatstorage.com" site.
* This is only an example...
* The "path" part of this endpoint URL is simply "/".
* Send the request to the WebDAV endpoint using
* the HttpSReq method:
loResp = CreateObject('Chilkat.HttpResponse')
lnSuccess = loHttp.HttpSReq("webdav.chilkatstorage.com",443,1,loReq,loResp)
IF (lnSuccess = 0) THEN
? loHttp.LastErrorText
RELEASE loReq
RELEASE loHttp
RELEASE loResp
CANCEL
ENDIF
* Get the XML response:
lcResponseXml = loResp.BodyStr
? "XML Response: " + lcResponseXml
* Get the response status code, such as 207
lnStatusCode = loResp.StatusCode
? "StatusCode = " + STR(lnStatusCode)
RELEASE loReq
RELEASE loHttp
RELEASE loResp