(Visual FoxPro) Duplicate PHP RSA Encryption

Demonstrates how to duplicate the following PHP function.

Chilkat ActiveX Downloads ActiveX for 32-bit and 64-bit Windows

LOCAL lcRsaMOD
LOCAL lcRsaEXP
LOCAL loBdMod
LOCAL loBdExp
LOCAL lnSuccess
LOCAL loXml
LOCAL loPubkey
LOCAL loRsa
LOCAL lcPlainText
LOCAL lcCipherText

* This example requires the Chilkat API to have been previously unlocked.
* See Global Unlock Sample for sample code.

* Duplicate the following PHP code:
* 
*    public function encryptRSA($plainText,$rsaMOD,$pubKEY){
*         $rsa  = new RSA();
*         $rsa->setEncryptionMode(RSA::ENCRYPTION_PKCS1);
*         $publicKey = [
*             'e' => new BigInteger($pubKEY,16),
*             'n' => new BigInteger($rsaMOD,16)
*         ];
* 		
*         $rsa->loadKey($publicKey);
*         $ciphertext = $rsa->encrypt($plainText);
*         return bin2hex($ciphertext);
*     }
* 
*     $plainText="key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678"
*     $rsaMOD="F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673"
*     $pubKEY="010001"

* We have the RSA modulus in hex
lcRsaMOD = "F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673"

* The RSA exponent in hex is "010001", which is 65537 in decimal.  It's typically the exponent that is always used.
lcRsaEXP = "010001"

* Get the RSA modulus and exponent in base64.
* For versions of Chilkat < 10.0.0, use CreateObject('Chilkat_9_5_0.BinData')
loBdMod = CreateObject('Chilkat.BinData')
* For versions of Chilkat < 10.0.0, use CreateObject('Chilkat_9_5_0.BinData')
loBdExp = CreateObject('Chilkat.BinData')
lnSuccess = loBdMod.AppendEncoded(lcRsaMOD,"hex")
lnSuccess = loBdExp.AppendEncoded(lcRsaEXP,"hex")

* Build the XML representation of the RSA public key
* For versions of Chilkat < 10.0.0, use CreateObject('Chilkat_9_5_0.Xml')
loXml = CreateObject('Chilkat.Xml')
loXml.Tag = "RSAPublicKey"
loXml.UpdateChildContent("Modulus",loBdMod.GetEncoded("base64"))
loXml.UpdateChildContent("Exponent",loBdExp.GetEncoded("base64"))

* Load the RSA public key into a Chilkat public key object.
* For versions of Chilkat < 10.0.0, use CreateObject('Chilkat_9_5_0.PublicKey')
loPubkey = CreateObject('Chilkat.PublicKey')
lnSuccess = loPubkey.LoadFromString(loXml.GetXml())

* Setup the RSA object for encryption and do it..
* For versions of Chilkat < 10.0.0, use CreateObject('Chilkat_9_5_0.Rsa')
loRsa = CreateObject('Chilkat.Rsa')
loRsa.VerboseLogging = 1
lnSuccess = loRsa.ImportPublicKeyObj(loPubkey)

* Use PKCSv1.5 padding
loRsa.OaepPadding = 0

* Encrypt and return the string as hex.
loRsa.EncodingMode = "hex"
lcPlainText = "key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678"
lcCipherText = loRsa.EncryptStringENC(lcPlainText,0)
IF (loRsa.LastMethodSuccess = 0) THEN
    ? loRsa.LastErrorText
    RELEASE loBdMod
    RELEASE loBdExp
    RELEASE loXml
    RELEASE loPubkey
    RELEASE loRsa
    CANCEL
ENDIF

* Note: The PKCSv1_5 padding incorporates random bytes.  Therefore, the RSA encryption will produce different results each time -- all of which are valid 
* and decrypt correctly to the same original text.
? lcCipherText

RELEASE loBdMod
RELEASE loBdExp
RELEASE loXml
RELEASE loPubkey
RELEASE loRsa