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(Visual FoxPro) AES-CMACDemonstrates using the AES-CMAC algorithm, which is a keyed hash function similar to HMAC and Poly1305. Note: Chilkat added AES-CMAC in version 9.5.0.95.
LOCAL loCrypt LOCAL lcKeyHex LOCAL lnSuccess LOCAL lcMessageBytes LOCAL loBd LOCAL lcCmac LOCAL lcPlainText LOCAL lcEncTag * This example assumes the Chilkat API to have been previously unlocked. * See Global Unlock Sample for sample code. * For versions of Chilkat < 10.0.0, use CreateObject('Chilkat_9_5_0.Crypt2') loCrypt = CreateObject('Chilkat.Crypt2') * Set the MAC algorithm to AES-CMAC loCrypt.MacAlgorithm = "aes-cmac" * AES-CMAC always uses a 16-byte (128-bit) MAC key. lcKeyHex = "2b7e151628aed2a6abf7158809cf4f3c" lnSuccess = loCrypt.SetMacKeyEncoded(lcKeyHex,"hex") * Let's compute the AES-CMAC for the test vector at https://www.rfc-editor.org/rfc/rfc4493#appendix-A * Here we have 64 bytes in hex representation. lcMessageBytes = "6bc1bee22e409f96e93d7e117393172aae2d8a571e03ac9c9eb76fac45af8e5130c81c46a35ce411e5fbc1191a0a52eff69f2445df4f9b17ad2b417be66c3710" * For versions of Chilkat < 10.0.0, use CreateObject('Chilkat_9_5_0.BinData') loBd = CreateObject('Chilkat.BinData') loBd.AppendEncoded(lcMessageBytes,"hex") * Compute the AES-CMAC for the bytes contained in bd and return the AES-CMAC in hex representation. loCrypt.EncodingMode = "hex_lower" lcCmac = loCrypt.MacBdENC(loBd) ? lcCmac * Output should be: 51f0bebf7e3b9d92fc49741779363cfe * Now do the same for a string: lcPlainText = "'Twas brillig, and the slithy toves" + CHR(10) + "Did gyre and gimble in the wabe:" + CHR(10) + "All mimsy were the borogoves," + CHR(10) + "And the mome raths outgrabe." lcEncTag = loCrypt.MacStringENC(lcPlainText) ? lcEncTag * Output should be: 4fca1fcbd265048d247f99ab57fa3ceb RELEASE loCrypt RELEASE loBd |
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