(Excel) XML Path Performance Optimizations

Discusses some important things to know about using Chilkat paths in the Chilkat XML API.

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Dim xml As Chilkat.Xml
Set xml = Chilkat.NewXml

' Let's load XML containing the following:

' <?xml version="1.0" encoding="utf-8"?>
' <xyz>
'     <licenses>
'         <license>
'             <id>1234</id>
'         </license>
'         <license>
'             <id>1234</id>
'         </license>
' ...
' My sample XML contains 64,000 "license" nodes ..
' ...
'         <license>
'             <id>1234</id>
'         </license>
'         <license>
'             <id>1234</id>
'         </license>
'     </licenses>
' </xyz>
' 

success = xml.LoadXmlFile("qa_output/large.xml")
If (success <> True) Then
    Debug.Print xml.LastErrorText
    Exit Sub
End If

' Iterating over the individual "license" nodes with this code snippet is
' extremely slow:

licCount = xml.NumChildrenHavingTag("licenses|license")
Debug.Print "license count = "; licCount


i = 0
' If "10" is changed to licCount, then it becomes apparent that this loop gets slower with each iteration.
Do While i < 10
    xml.I = i
    s = xml.GetChildContent("licenses|license[i]|id")
    Debug.Print i; ": "; s
    i = i + 1
Loop

' The reason it is extremely slow is that the "license[i]" part of the path passed to GetChildContent
' says: find the i'th child of "licenses" having the tag "license".  Chilkat cannot assume that all
' children of an XML node have the same tag.  Therefore it's not possible to directly access the i'th child.
' Internally, Chilkat must start at the 1st child and iterate until it reaches the i'th child having the
' tag "license".

' For example, imagine if the XML was like this:

' <?xml version="1.0" encoding="utf-8"?>
' <xyz>
'     <licenses>
'         <license>
'             <id>1234</id>
'         </license>
'         <somethingElse>
'             <a>abc</a>
'         </somethingElse>
'         <license>
'             <id>1234</id>
'         </license>
' ...

' In the above XML, the 1st "license" is the 1st child of "licenses", but the 2nd "license"
' is the 3rd child of "licenses".

' If you already know that all children have the same tag, there is a shortcut that allows
' for direct access to that child.  Just leave off the tag name, like this:

i = 0
' If "10" is changed to licCount, then we can see the time for each loop is the same, and it's fast.
Do While i < 10
    xml.I = i
    s = xml.GetChildContent("licenses|[i]|id")
    Debug.Print i; ": "; s
    i = i + 1
Loop

' When we pass just the index "[i]", we're saying: Get the i'th child regardless of tag.
' This is extremely fast because internally we can just access the i'th child directly.

' Another performance improvement is to call NumChildrenAt rather than NumChildrenHavingTag.
' For example:
licCount = xml.NumChildrenAt("licenses")
Debug.Print "licCount = "; licCount

' NumChildrenAt returns the total number of children at the tag path.  If we already know
' all children will have the same tag, we can just get the count