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(Excel) HTTPS multipart/form-data POST

Demonstrates how to send a multipart/form-data POST over HTTPS (using TLS).

Download Excel Class Modules

Chilkat Excel Class Modules

'  This example assumes the Chilkat HTTP API to have been previously unlocked.
'  See HTTP Unlock Sample for sample code.

'  This example demonstrates how to send a multipart/form-data POST that
'  looks like this:

'  	POST /cgi/XXX.pl HTTP/1.0
'  	Accept: text/html
'  	Connection: Keep-Alive
'  	User-Agent: XXX/8.0.15
'  	Content-type: multipart/form-data, boundary=XXXxyxy
'  	Content-Length: 682
' 
'  	--XXXxyxy
'  	content-disposition: form-data; name="UploadAgent"
' 
'  	InterfaceVersion1.5
'  	--XXXxyxy
'  	content-disposition: form-data; name="user"
' 
'  	XXX
'  	--XXXxyxy
'  	content-disposition: form-data; name="password"
' 
'  	XXX
'  	--XXXxyxy
'  	content-disposition: form-data; name="file"
' 
'  	XXX
'  	--XXXxyxy
'  	content-disposition: form-data; name="data_version"
' 
'  	XXX:??
'  	--XXXxyxy
'  	content-disposition: form-data; name="content2"; filename="XXX"
' 
'  	THE FILE CONTENT GOES HERE...
'  	--XXXxyxy--
' 

'  First, let's build the HTTP request object
Dim req As Chilkat.HttpRequest
Set req = Chilkat.NewHttpRequest

req.HttpVerb = "POST"
req.Path = "/cgi/XXX.pl"

'  The boundary string is automatically generated and added by Chilkat.
'  The value for the boundary string doesn't matter. (As long as it's a unique string that doesn't occur elsewhere in the request.)
req.ContentType = "multipart/form-data"

'  Adding the Connection: Keep-Alive is optional.  It only makes sense if the intent is to send
'  additional requests to the same domain (your-namespace-sb.accesscontrol.windows.net) within a reasonable time period.
req.AddHeader "Connection","Keep-Alive"

'  --------------------------------------------------
'  IMPORTANT: Never set the Content-Length header.
'  Chilkat will automatically compute the correct Content-Length and will add it.
'  --------------------------------------------------

'  If a specific User-Agent header field is needed, it can be added by calling AddHeader.
req.AddHeader "User-Agent","XXX/8.0.15"

'  The "Accept" header, if present, tells the server what Content-Type responses will be accepted.
'  In this case, we're telling the server that we'll only accept "text/html" responses, and therefore
'  the server SHOULD only send a text/html response.  Technically, the Accept header is not required.
req.AddHeader "Accept","text/html"

'  Add the params to the request.  Given that the Content-Type is set to "multipart/form-data", when
'  Chilkat composes the request, it will put each param in it's own MIME sub-part (i.e. in it's own
'  part delimited by the boundary string).
req.AddParam "UploadAgent","InterfaceVersion1.5"
req.AddParam "user","XXX"
req.AddParam "password","XXX"
req.AddParam "file","XXX"
req.AddParam "data_version","XXX"

'  The last param is the contents of a file.
'  If it's a file on disk, we can add it like this:

pathToFileOnDisk = "c:/someDir/someFile.dat"

success = req.AddFileForUpload("content2",pathToFileOnDisk)
If (success <> True) Then
    Debug.Print req.LastErrorText
    Exit Sub
End If

'  Alternatively, if the contents of the file are in memory, perhaps in a string
'  variable, the file can be added like this instead.

fileContents = "This is the content of the file being uploaded."
success = req.AddStringForUpload("content2","XXX",fileContents,"utf-8")

'  -----------------------------------------------------------
'  IMPORTANT: To duplicate the HTTP request shown above, you'll want to choose
'  either AddStringForUpload or AddFileForUpload, but not both.  It's possible to upload
'  any number of files by calling AddStringForUpload and/or AddFileForUpload any number
'  of times, once per file to be uploaded.  This of course assumes that the receiving
'  end is programmed to receive multiple files..
'  ------------------------------------------------------------

Dim http As Chilkat.Http
Set http = Chilkat.NewHttp

'  The request is ready... now send it using HTTPS (which is port 443 by default).


Set resp = http.SynchronousRequest("www.myserver.com",443,True,req)
If (http.LastMethodSuccess <> True) Then
    Debug.Print http.LastErrorText
    Exit Sub
End If

Debug.Print "HTTP response status: "; resp.StatusCode

'  In this case, the response would be HTML because our Accept header
'  told the server to only return HTML.  The HTML is available on the BodyStr
'  property of the response object:

htmlStr = resp.BodyStr
Debug.Print "Received:"
Debug.Print htmlStr


 

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